9/4y-2=25
9/4y-2+2=27+2
9/4y=27
9/4y*4y=27*4y
9=4y*27,
1/3=4y, (9/27 simpltfies to 1/3, 1/3 divided by 4: 1/3*1/4=1/12)
1/12=y
Answer:y=1/12
Answer:
45
Step-by-step explanation:
divide 25 by 5 to see how they got that, which is 5. then multiply 9 by 5 bc you have to do the same thing, which is 45.
Answer:

Step-by-step explanation:
Given

Required
Determine KBC
Since BK is a bisector of ABC at B,
this implies that:

Substitute 28.3 for ABK

Reorder

To solve this, we have to find the volume of the cylinder first. The formula to be used is

Given:V= ?r= 6cmh= 10cm
Solution:

V= (3.14)(6cm)

x 10cmV= (3.14)(

) x 10cmV= (

) x 10cmV= 1130.4cm^3
Finding the volume of the cylinder, we can now solve what the weight of the oil is. Using the formula of density, Density = mass/volume, we can derive a formula to get the weight.
Given:Density = 0.857 gm/cm^3Volume = 1130.4 cm^3
Solution:weight = density x volumew= (0.857 gm/cm^3) (1130.4cm^3)w= 968.7528 gm
The weight of the oil is 968.75 gm.