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3 years ago

use the formula to calculate how much the district spent on athletics in 1999. round your answer to the nearest thousandth

Mathematics

1 answer:

Vesnalui [34]3 years ago

4 0

10.6325909767 rounded to the nearest 10th is 10.633

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A car salesman had $65100 in total monthly sales last month. He made $1953 in commission from those sales. What is the salesmans

konstantin123 [22]

Answer:

Step-by-step explanation:

In order to find out the percent in commissions a car salesman received, you need to divide $1953 by $65100. The result is .03, which translates to 3%.

Hope that helps!

6 0

3 years ago

3x^2+2x+5=0 Quadratic equation

KIM [24]

Step-by-step explanation:

use formula

(-b+√b2-4ac)/2a

a=3, b=2 , c=5

(-2+√4-4×3×5)/2×3

(-2+√-56)/6

(-2+2√-14)/6

(-2 +2√14i)/6

7 0

2 years ago

Read 2 more answers

What is 4/9 divded by 1/3

andrezito [222]

Easiest way is to flip the divisor and multply.

4/9 divided by 1/3
is the same as 4/9 times 3/1

Should be pretty easy to go the rest of the way yourself.

6 0

3 years ago

Read 2 more answers

Maths, Spanish and English

inn [45]

what do you need help for

3 0

2 years ago

Assume that body masses of Goldfinch birds follow a normal distribution with standard deviation equal to 0.04 oz. An ornithologi

il63 [147K]

Answer:

The formula to generate 70% confidence interval is: $[\overline{x} - 0.013, \overline{x} + 0.013]$ , in which $\overline{x}$ is the sample mean.

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1 - 0.7}{2} = 0.15$

Now, we have to find z in the Z-table as such z has a p-value of $1 - \alpha$ .

That is z with a pvalue of $1 - 0.15 = 0.85$ , so Z = 1.037.

Now, find the margin of error M as such

$M = z\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

Assume that body masses of Goldfinch birds follow a normal distribution with standard deviation equal to 0.04 oz.

This means that $\sigma = 0.04$ .

Sample of 10 birds:

This means that $n = 10$ .

The margin of error is of:

$M = z\frac{\sigma}{\sqrt{n}}$

$M = 1.037\frac{0.04}{\sqrt{10}}$

$M = 0.013$

The lower end of the interval is the sample mean of $\overline{x}$ subtracted by M.

The upper end of the interval is the sample mean of $\overline{x}$ added to M.

Then, the formula to generate 70% confidence interval is: $[\overline{x} - 0.013, \overline{x} + 0.013]$ , in which $\overline{x}$ is the sample mean.

8 0

3 years ago