Matt could do one of the following arrangements;
2 rows of 8 CDs
4 rows of 4 CDs
Answer:
4:1
Step-by-step explanation:
x+20 : y+20 = 5 : 2
(x+20)/(y+20) = 5/2
2(x+20) = 5(y+20)
2x+40 = 5y+100
2x = 5y+60 (1)
x-5 : y-5 = 5:1
(x-5)/(y-5) = 5/1
x-5 = 5(y-5)
x-5 = 5y-25
x = 5y-20 (2)
Solve (1) & (2) simultaneously,
2(5y-20) = 5y+60
10y-40 = 5y+60
5y = 100
y = 20
x = 5y-20
x = 5(20)-20 = 100-20
x = 80
x:y
80:20
4:1
Answer:
C=45
if 9/11 = c/55 you have to divide the c/55 by 9/11, resulting in c/9 = 5
multiply 9 by 5 to get 45
Step-by-step explanation:
A. C(13, 10) = 13! = 13·12·11 = 13 · 2 · 11 = 286.C(13, 10) = 13! = 13·12·11 = 13 · 2 · 11 = 286.
B. P(13,10)= 13! =13! =13·12·11·10·9·8·7·6·5·4.
(13−10)! 3!
C. f there is exactly one woman chosen, this is possible in C(10, 9)C(3, 1) =
10! 3!
9!1! 1!2!
10! 3!
8!2! 2!1!
10! 3!
7!3! 3!0!
= 10 · 3 = 30 ways; two women chosen — in C(10,8)C(3,2) =
= 45·3 = 135 ways; three women chosen — in C(10, 7)C(3, 3) =
= 10·9·8 ·1 = 120 ways. Altogether there are 30+135+120 = 285
1·2·3
<span>possible choices.</span><span>
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