Select the point that is a solution to the system of inequalities.<br> y< x2 + 6<br> y> x2

REY [17]

The answer would be A.
Because you are subtracting the exponents.
Hope it helps.

7 0

3 years ago

The smallest object visible with your eyes is similar to the width of a piece of hair, which is 1×10−4 meters wide. Using an opt

Sloan [31]

Answer:

B. $5\times10^{2}$

Step-by-step explanation:

We are told that the smallest object visible with our eyes is similar to the width of a piece of hair, which is $1\times 10^{-4}$ meters wide.

Using an optical microscope, we can see items up to $2\times 10^{-7}$ meters wide.

To find the objects we can see with our eyes are how much larger than the objects we can see with an optical microscope, we can set an equation as:

$\frac{\text{The width of the object we can see with our eyes}}{\text{The width of the objects we can see with microscope}}=\frac{1*10^{-4}}{2*10^{-7}}$

Using the exponent rule of quotient $\frac{a^m}{a^n}=a^{m-n}$ we will get,

$\frac{\text{The width of the object we can see with our eyes}}{\text{The width of the objects we can see with microscope}}=\frac{1}{2}*10^{-4-(-7)}$

$\frac{\text{The width of the object we can see with our eyes}}{\text{The width of the objects we can see with microscope}}=0.5*10^{-4+7}$

$\frac{\text{The width of the object we can see with our eyes}}{\text{The width of the objects we can see with microscope}}=0.5*10^{3}$

$\frac{\text{The width of the object we can see with our eyes}}{\text{The width of the objects we can see with microscope}}=0.5*10\times 10^{3-1}$

$\text{The object we can see with our eyes}=5\times10^{2}*\text{The objects we can see with microscope}$

Therefore, the objects we can see with our eyes are $5\times10^{2}$ times larger than the objects we can see with an optical microscope and option B is the correct choice.

3 0

3 years ago

six times a number is greater than 20 more than that number.what are the possible values of that number?

sergiy2304 [10]

Answer:

All the values greater than the number 4 are possibles values for this number:

Step-by-step explanation:

Let x is the number mentioned:

Six times a number : 6 ( x )

Twenty more than the number: 20 + x

6 x > 20 + x

Solving the inequality

6 x - x > 20

5x > 20

x > $\frac{20}{5}$

x > 4

3 0

3 years ago

Solve the inequality 7x-6<14x+8 write the solution in interval form??? ....[2.4]

Likurg_2 [28]

(-2,infinite]

negative two and the infinite symbol

3 0

3 years ago

A rectangle has an area of 72 in². The length and the width of the rectangle are changed by a scale factor of 3.5. What is the a

kifflom [539]

Answer:

The area of the new rectangle is 882 in².

Step-by-step explanation:

Let l be the length and w be the width of the original rectangle,

So, the area of the original rectangle is,

A = l × w ( Area of a rectangle = Length × Width )

Given, A = 72 in²,

⇒ lw = 72 ------- (1),

Since, if the rectangle are changed by a scale factor of 3.5,

⇒ New length = 3.5 l,

And, new width = 3.5 w,

Thus, the area of the new rectangle = 3.5l × 3.5w

$=(3.5)^2lw$

$=12.25\times 72$ ( From equation (1) ),

= 882 in²

4 0

3 years ago

Select the point that is a solution to the system of inequalities. y< x2 + 6 y> x2 - 4