For the answer to the question above,
<span>V(n) = a * b^n, where V(n) shows the value of boat after n years.
V(0) = 3500
V(2) = 2000
n = 0
V(0) = a * b^0 = 3500
a = 3500
V(2) = a * b^2
2000 = 3500 * b^2
b = sqrt (2000/3500)
b ≈ 0.76
V(n) = 3500 * 0.76^n
We can check it for n = 1 which is close to 2500 in the graph:
V(1) = 3500 * (0.76)^1
V(1) = 2660
And in the graph we have V(3) ≈ 1500,
V(n) = 3500 * (0.76)^3 ≈ 1536
Now n = 9.5
V(9.5) = 3500 * (0.76)^(9.5)
V(9.5) ≈ 258</span>
40,000 is your answer hope I could help
The answers to the questions are
- The mathematical model is given as s = −16t2 + 1054
- The height after 4.5 seconds is 730 feet
- the time it would take to strike the ground is 8.11 seconds.
<h3>How to solve for the position of the object</h3>
The mathematical model of this problem would be written as
s = −16t2 + v0t + s0
s0 = 1054
then we would have
s = −16t2 + 1054
b. after 4.5 seconds the height is going to be
s = −16t2 + 1054
= −16(4.5)² + 1054
= -16 * 20.25 + 1054
= 730
C. the time that it takes to strike the ground
s = −16t² + 1054
= 16t² = 1054
t² = 1054/16
= 65.88
t = √65.88
t = 8.11
Hence the time it would take to strike the ground is 8.11 seconds.
Read more on velocity here:
brainly.com/question/4931057
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