Answer:
The domain of the inverse of a relation is the same as the range of the original relation. In other words, the y-values of the relation are the x-values of the inverse.
Thus, domain of f(x): x∈R = range of f¯¹(x)
and range of f(x): x∈R =domain of f¯¹(x)
F(f-1x) will be equal to x
take a simple example
f(x) = 2x
so x = f(x) / 2
f-1(x) = x/2
f(f-1x) = 2 ( x/2) = 2 * x/2 = x
The equivalent to (1/3)^3 is
(1/3) x (1/3) x (1/3) = .<span>037
</span>
The answer is 1/27 or 0.37.
The answer is: (z - 6)(z + 15)
z² + 9z - 90 = z*z + 15z - 6z - 6*15 =
= (z*z + 15z) - (6z + 6*15) =
= z(z + 15) - 6(z + 15) =
= (z - 6)(z + 15)
Answer:
for the first on its a=24 and for the second its a= 48
Step-by-step explanation:
for the first one you have to find the length which is 8 and then you find the width which is 3 then you multiply that to get 24
for the second one you find the base which is the strait line which is 8 then you find the height which is 6 then you multiply it to get 48 i hopes this helped!
