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3 years ago

Find the area of the rectangle.

Mathematics

2 answers:

kari74 [83]3 years ago

4 0

A=35/72
explanation:
formula for area is a=lw
a=?
l (length) = 7/8
w (width) = 5/9
multiply.

Leno4ka [110]3 years ago

3 0

Length multiplied by Width is Area, or A = L x W. 5/9 x 7/8 is your answer.

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What’s the identity property of addition?

Novosadov [1.4K]

Answer:

Identity property of addition: The sum of 0 and any number is that number. For example, 0 + 4 = 4 0 + 4 = 4 0+4=40, plus, 4, equals, 4.

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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2 years ago

Because of staffing decisions, managers of the Gibson-Marion Hotel are interested in the variability in the number of rooms occu

olchik [2.2K]

Answer:

a) $s^2 =30^2 =900$

b) $\frac{(19)(30)^2}{30.144} \leq \sigma^2 \leq \frac{(19)(30)^2}{10.117}$

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Step-by-step explanation:

Assuming the following question: Because of staffing decisions, managers of the Gibson-Marimont Hotel are interested in the variability in the number of rooms occupied per day during a particular season of the year. A sample of 20 days of operation shows a sample mean of 290 rooms occupied per day and a sample standard deviation of 30 rooms

Part a

For this case the best point of estimate for the population variance would be:

$s^2 =30^2 =900$

Part b

The confidence interval for the population variance is given by the following formula:

$\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}$

The degrees of freedom are given by:

$df=n-1=20-1=19$

Since the Confidence is 0.90 or 90%, the significance $\alpha=0.1$ and $\alpha/2 =0.05$ , the critical values for this case are:

$\chi^2_{\alpha/2}=30.144$

$\chi^2_{1- \alpha/2}=10.117$

And replacing into the formula for the interval we got:

$\frac{(19)(30)^2}{30.144} \leq \sigma^2 \leq \frac{(19)(30)^2}{10.117}$

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Part c

Now we just take square root on both sides of the interval and we got:

$23.818 \leq \sigma \leq 41.112$

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3 years ago

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