We call:

as the set of <span>the first 51 consecutive odd positive integers, so:
</span>

Where:





<span>and so on.
In mathematics, a sequence of numbers, such that the difference between two consecutive terms is constant, is called Arithmetic Progression, so:
3-1 = 2
5-3 = 2
7-5 = 2
9-7 = 2 and so on.
Then, the common difference is 2, thus:
</span>

<span>
Then:
</span>

<span>
So, we need to find the sum of the members of the finite series, which is called arithmetic series:
There is a formula for arithmetic series, namely:
</span>

<span>
Therefore, we need to find:
</span>
Given that

, then:

Thus:

Lastly:
Answer:
Step-by-step explanation:
I think it is C
1:6
i got my answer for using ratios
Answer:
Answers are below.
Step-by-step explanation:
Hope this helps:)
Answer:
1440 combinations ways
Step-by-step explanation:
We know that the total arrangements will be
6!= 720 because its a 6letter word
So if we take MI to be a one letter word
Same for IM
which will Also be 6!= 720
SO TOTAL possible combination will be 720+720= 1440