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4 years ago

Convert 65 mm to meters

Mathematics

1 answer:

Ymorist [56]4 years ago

7 0

0.065 meters is equal to 65 millimeters

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Amanda [17]

Answer:

sorry i cant answer that one man.

Step-by-step explanation:

5 0

3 years ago

X over 2 +2= 15 two step equations

Fed [463]

Answer:

$\boxed{\boxed{\sf x=84}}$

Step-by-step explanation:

$\sf \cfrac{x}{6} +2=16$

Multiply both sides of the equation by 6:

$\sf x+12=96$

Subtract 12 from both sides:

$\sf x=96-12$

Subtract 12 from 96:

$\sf x=84$

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3 0

2 years ago

Read 2 more answers

Write a polynomial function of minimum degree in standard form with real coefficients whose zeros and their multiplicities inclu

Softa [21]

Answer-

The polynomial function is,

$y=x^4-10x^3+38x^2-64x+40$

Solution-

The zeros of the polynomial are 2 and (3+i). Root 2 has multiplicity of 2 and (3+i) has multiplicity of 1

The general form of the equation will be,

$\Rightarrow y=(x-(2))^2(x-(3+i))(x-(3-i))$ ( ∵ (3-i) is the conjugate of (3+i) )

$\Rightarrow y=(x-2)^2(x-3-i)(x-3+i)$

$\Rightarrow y=(x^2-4x+4)((x-3)-i)((x-3)+i)$

$\Rightarrow y=(x^2-4x+4)((x-3)^2-i^2)$

$\Rightarrow y=(x^2-4x+4)((x^2-6x+9)+1)$

$\Rightarrow y=(x^2-4x+4)(x^2-6x+10)$

$\Rightarrow y=x^2x^2-6x^2x+10x^2-4x^2x+4\cdot \:6xx-4\cdot \:10x+4x^2-4\cdot \:6x+4\cdot \:10$

$\Rightarrow y=x^4-10x^3+14x^2+24x^2-40x-24x+40$

$\Rightarrow y=x^4-10x^3+38x^2-64x+40$

Therefore, this is the required polynomial function.

4 0

3 years ago

3600 dollars is placed in an account with an annual interest rate of 9%. How much will be in the account after 25 years, to the

Arlecino [84]

Answer:

31043.09

Step-by-step explanation:

Kinda feel bad for the last person who answered! They were way off but still you need to learn from your mistakes! Welp this answer is STRAIGHT OFF THE BACK from delta MATH! So this IS correct! If this helped click the stars and the heart to help fellow students, educators, etc. Understand this answer is for certain correct! I would add the steps but there is alot!

3 0

3 years ago

HELP ASAP!!!!! Given: Point B is on the perpendicular bisector of AC¯¯¯¯¯. BD¯¯¯¯¯ bisects AC¯¯¯¯¯ at point D. Prove: B is equid

Harlamova29_29 [7]

Answer: Missing parts are,

In first blank, $AD\cong DC$ ,