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garri49 [273]
3 years ago
13

I need help *********

Mathematics
2 answers:
Dmitry [639]3 years ago
8 0

Answer:

the answer to this question is d.

Anna007 [38]3 years ago
7 0

Answer:

D.

Step-by-step explanation:

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Does anyone know how to do this. that can please show me the work ?? <br> -view attachment
suter [353]
SOH CAH TOA
Sine=opposite leg/hypotenuse
Cosine=adjacent leg/hypotenuse
Tangent=opposite leg/adjacent leg
SOH CAH TOA
So d is the correct answer
6 0
3 years ago
Find the scale factor that was used to change
avanturin [10]

Answer:

C. 1/5

Step-by-step explanation:

Original * scale factor = Scaled

25 * SF = 5

Divide each side by 25

25/25 * SF = 5/25

SF = 1/5

4 0
2 years ago
Read 2 more answers
What is 56cm added to 2m 50cm?
Over [174]
100cm = 1m so 2m 50cm = 250cm + 56cm= 306cm which means the answer is 3m 6 cm
3 0
3 years ago
Let the sample size of leg strengths to be 7 and the sample mean and sample standard deviation be 630 watts and 32 watts, respec
Colt1911 [192]

Answer:

a. There is_<u><em>sufficient</em></u> evidence that the leg

C. 0.010 < P-value < 0.025

b. Power of test = 1- β=0.2066

c. So the sample size is 88

Step-by-step explanation:

We formulate the null and alternative hypotheses as

H0 : u1= u2 against Ha : u1 > u2 This is a right tailed test

Here n= 7 and significance level ∝= 0.005

Critical value for a right tailed test with 6 df is 1.9432

Sample Standard deviation = s= 32

Sample size= n= 7

Sample Mean =x`= 630

Degrees of freedom = df = n-1= 7-1= 6

The test statistic used here is

Z = x- x`/ s/√n

Z= 630-600 / 32 / √7

Z= 2.4797= 2.48

P- value = 0.0023890 > ∝ reject the null hypothesis.

so it lies between 0.010 < P-value < 0.025

b) Power of test if true strength is 610 watts.

For  a right tailed test value of z is = ± 1.645

P (type II error) β= P (Z< Z∝-x- x`/ s/√n)

Z = x- x`/ s/√n

Z= 610-630 / 32 / √7

Z=0.826

P (type II error) β= P (Z< 1.645-0.826)

= P (Z> 0.818)

= 0.7933

Power of test = 1- β=0.2066

(c)

true mean = 610

hypothesis mean = 600

standard deviation= 32

power = β=0.9

Z∝= 1.645

Zβ= 1.282

Sample size needed

n=( (Z∝ +Zβ )*s/ SE)²

n=  ((1.645+1.282) 32/ 10)²

Putting the values  and solving we get 87.69

So the sample size is 88

5 0
3 years ago
Identify the slope and the y-intercept of the line with the given equation:<br> y = 7x-5
svetlana [45]

Answer:

Slope = 7

Y intercept = (0,-5)

7 0
3 years ago
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