Work done on trunk = force * distance = 2 * 3 = 6 joules
Gain in potential energy = 0 joules
Answer:
F(n) = 2n – 2
Step-by-step explanation:
The sequence 0, 2, 4, 6
First, let us determine if the sequence is arithmetic progression (A.P) or geometric progression (G.P)
This is illustrated:
Let us calculate the common difference (d)
Common difference (d) = 2nd term – first term
Common difference (d) = 3rd term – 2nd term
=> 2 – 0 = 2
=> 4 – 2 = 2
The common difference (d) = 2.
Common ratio (r) = 2nd term /1st term
Common ratio (r) = 3rd term /2nd term
=> 2/0 = undefined
=> 4/2 = 2
There is no common ratio.
Since we have a common difference, therefore the sequence is arithmetic progression.
Now, let us obtain an expression for the sequence.
This can be obtained by using the arithmetic progression formula as shown below:
F(n) = a + (n – 1)d
a is the first term
n is the number of term
d is the common difference.
The sequence 0, 2, 4, 6
The first term (a) = 0
Common difference (d) = 2
F(n) = a + (n – 1)d
F(n) = 0 + (n – 1)2
F(n) = 2n – 2
N divided by 6=270
1st step: do the opposite of dividing which is multiplying. 270*6=1620
n=1620
2nd step check your answer 1620 /6 =270
I plugged the answer in n so we can check.
Answer:
(1;1)
Step-by-step explanation:
1. if y=2x-1, then it is possible to substitute 2x-1 into the 2d equation:
5x-4(2x-1)=1, ⇒ 5x-8x+4=1, ⇔ -3x=-3, ⇔ x= 1;
2. if x=1, then y=2x-1=2-1= 1.
3. the required pair is (1;1)
Hey there :)
h ( x ) = f [ g ( x ) ]
To find h ' ( x )
We do → f ' [ g ( x ) ] × g ' ( x )
This is called the chain rule
Given;
g ( 1 ) = 2 → f ' ( 2 ) = 5
g ' ( 1 ) = 6
Apply the formula
h ' ( 1 ) = f ' [ g ( 1 ) ] × g ' ( 1 )
= f ' ( 2 ) × 6
= 5 × 6
h ' ( 1 ) = 30
