Essentially when people ask you find the solution to system of equation, there asking at what x value do these to graphs intersect. The easiest way to do this is to get a graphing calculator, or desmos and type in the equation and find where they intersect. Heck, even the question says to solve it with a graph, but I'll demonstrate it algebraically.
One way you can do this is set the equation equal to each other. This is because you want to know at what x-value has the same y-value. So we get:
x^2 + 6x + 8 = x + 4
We can then combine like terms, or move everything to one side. So we get:
x^2 + 5x + 4 = 0.
Then we can use the quadratic formula to solve for x.
x=(-5 +/- sqrt(5^2 - 4(1)(4)))/(2(1)
This simplifies into:
(-5 +/- 3)/2
Finally we add and subtract:
(-5 + 3)/2 = x = -1
(-5 - 3)/2 = x = -4
And our solution is x = -1, x = -4
Answer:
-7
Step-by-step explanation:
substitute both x's for 7:
(-8(7)+4)+ (3(7)2+5)
= -54 + 47
= -7
If the slopes of the 2 lines are equal then they are parallel.
If m1m2 = -1 (where m1 and m2 are the slopes of the 2 lines) then they are perpendicular.
If the 2 slopes do not match either the first or second conditions then they are neither parallel or perpendicular.
