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nasty-shy [4]
4 years ago
6

What is the answer to this question?

Mathematics
1 answer:
kirza4 [7]4 years ago
4 0
I hope this helps you

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Solve this polynomial:
d1i1m1o1n [39]

hope it helps

plz mark brainliest

7 0
3 years ago
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There are two values of a for which the equation 5x2+ax+7x+5=0 has only one solution for x. What is the sum of those values of a
JulsSmile [24]

Answer:

-14

Step-by-step explanation:

First of all, we know that 5x^2+ ax+7x +5=0 only has one root. That means that b^2 - 4ac=0, and we can use this to find the discriminant, ax + 7x.

Now, if we simplified 5x^2+ ax+7x +5=0, by dividing it all by 5, it would be x^2+(a+7)/5x + 1 = 0.

After, we can plug what we know into the formula, b^2 - 4ac=0. It would be:

(a+7)^2 / 25 - 4 = 0

(a+7)^2 / 25 = 4

(a+7)^2 = 100

Since this is a square root, a+7 can be both negative or positive.

a+7= 10, or a+7 = -10

a=3, or a=-17

The question asks for the sum of a, which is 3 + (-17) = -14

Therefore, the answer is -14.

:) have fun with your rsm problems, assuming you got this from the portal.

7 0
3 years ago
Choose either Multiplication and Division
Sliva [168]

Answer:

multiplication and divisioni gusss cause area will be give amd all" × " u have to put in "÷" fiorm

6 0
3 years ago
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Hello! Please help me with this. I'm very desperate lol. Its 16. Ill give brainliest
Paladinen [302]

Answer:

You showed the right work and got the right answer!

x = 6

Step-by-step explanation:

Since B is in the middle of A and C, AB + BC = AC

So,

2x - 11 + 8 = x + 3

x - 3 = 3

x = 6

7 0
1 year ago
Write the equation in standard form for the circle with center (0, – 10) and radius 6.
Artemon [7]

Answer:

Equation of circle in standard form with centre (0, – 10) and radius 6. \mathbf{x^2+(y+10)^2=36}

Step-by-step explanation:

We need to write equation of circle in standard form with centre (0, – 10) and radius 6.

The equation of circle is: (x-h)^2+(y-k)^2=r^2

where (h,k) is centre of circle and r is radius

We are given centre (0,-10) so, h=0, k=-10 and radius r = 6

Putting values and finding equation:

(x-h)^2+(y-k)^2=r^2\\(x-0)^2+(y-(-10))^2=(6)^2\\x^2+(y+10)^2=36

So, equation of circle in standard form with centre (0, – 10) and radius 6. \mathbf{x^2+(y+10)^2=36}

5 0
3 years ago
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