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Doss [256]
2 years ago
9

A rectangle is 8 inches long and 4 inches wide. A similar rectangle is 12 inches long. What is the width of the second rectangle

to the nearest inch?
Mathematics
1 answer:
Charra [1.4K]2 years ago
6 0
The ratio between the length and the width of the first rectangle=
l/w=2/1

Apply this to the second rectangle which have the length of 12 inches pong, so we just need to take 12÷2=6 inches. As a result, the width of the second rectangle is 6 inches. Hope it help!
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Please help with this question
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Answer:

  12\sin{(2\theta)}\cos{(\theta)}

Step-by-step explanation:

The appropriate trig identity is ...

  \sin{a}+\sin{b}=2\sin{\left(\dfrac{a+b}{2}\right)}\cos{\left(\dfrac{a-b}{2}\right)}

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