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3 years ago

The list below shows the number of minutes Addison spent reading on each of six days. 90, 60, 89, 94, 60, 93

Mathematics

1 answer:

CaHeK987 [17]3 years ago

4 0

Mean and Median best describe the typical number of minutes she spent reading each day.

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Which is shorter 3/6 of a minute or 2/6 of an hour

Juliette [100K]

3/6 of a minute because an hour is much longer

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3 years ago

Read 2 more answers

Evaluate (-A)^2 for A = 5, B = -4, and C = 2

drek231 [11]

Answer:

(-A)^2 for A = 5

(-5)^2

=25

Step-by-step explanation:

first, replace A by 5, and maintain the negative to the 5.

multiply (-5)^2.

nb: don't forget to maintain the bracket when multiplying. if you maintain the bracket, you'll get a positive number, but if you don't, you'll get a negative number.

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3 years ago

HELPP MEE PLSSS HELPP

julia-pushkina [17]

Answer:

angle N is 79, angle K is 22, angle P is 81, angle D is 76

Step-by-step explanation:

all of the angles should add up to 180 degrees so add the two angles you have and subtract them from 180

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2 years ago

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X + 4y = 18 3x − y = 2 given x + 4y = 18 12x − 4y = 8 x + 4y + 8 = 18 + 8 x + 4y + (12x − 4y) = 18 + 8 13x = 26 justification st

goldenfox [79]

Spacing needs to be more clear instead of having a giant paragraph. you do not write math in giant paragraphs do you

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3 years ago

A dog weighs two pounds less than three times the weight of a cat. The dog also weights twenty-two more pounds than the cat. Wri

8090 [49]

Answer:

Weight of dog: 34 pounds,

Weight of cat: 12 pounds.

Step-by-step explanation:

Let d represent weight of dog and c represent weight of cat.

We have been given that a dog weighs two pounds less than three times the weight of a cat.

3 times weight of cat: $3c$

We can represent the given information in an equation as:

$d=3c-2...(1)$

We are also told that the dog also weights twenty-two more pounds than the cat. We can represent the given information in an equation as:

$d=c+22...(2)$

Equate both equations:

$3c-2=c+22$

$3c-c-2=c-c+22$

$2c-2=22$

$2c-2+2=22+2$

$2c=24$

$\frac{2c}{2}=\frac{24}{2}$

$c=12$

Therefore, the weight of cat is 12 pounds.

Substitute $c=12$ in equation (2)

$d=c+22$

$d=12+22$

$d=34$

Therefore, the weight of dog is 34 pounds.

4 0

3 years ago