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sattari [20]
3 years ago
10

What is an extraneous solution? a solution that was found due to an arithmetic error a solution that satisfies the original equa

tion an apparent solution that is not a real number an apparent solution that does not satisfy the original equation

Mathematics
2 answers:
lesantik [10]3 years ago
7 0

Answer:

  an apparent solution that does not satisfy the original equation

Step-by-step explanation:

Usually, an extraneous solution is introduced by the solution process. Sometimes it takes the form of multiplying an equation by 0, often the result of eliminating the denominators of rational functions.

Other times, it takes the form of adding branches to a function that are unintended or undefined. (Squaring a square root will often introduce "solutions" that require the square root to be a negative value.) The attached graph shows that x=4 is an extraneous solution to ...

  √x = x-6

It shows up when the equation is squared:

  x = x² -12x +36   ⇒   (x -9)(x -4) = 0

The "solution" x=4 is extraneous because it does not satisfy the original equation.

As in this graphed example, using graphical methods to find solutions can often avoid extraneous solutions.

Tema [17]3 years ago
7 0

Answer:

 an apparent solution that does not satisfy the original equation

Step-by-step explanation:

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Find the value of x. O is the center of the circle. Round your answer to the nearest hundredth.
katrin [286]

x=5.38 . Correct option C)5.38

<u>Step-by-step explanation:</u>

Here we have , Find the value of x. O is the center of the circle. Round your answer to the nearest hundredth.  picture is attached  . Let's find out:

In the given figure , Let's draw a line from center to the point where cord of length 8 unit is touching the circle or intersecting or , where this chord finishes . This line is radius of circle and is denoted by x , So now we have a right angle triangle with dimensions as :

Perpendicular =3.6\\Base=\frac{8}{2}=4\\Hypotenuse=x

By Pythagoras Theorem ,

Hypotenuse^2=Perpendicular^2+base^2

⇒ x^2=(3.6)^2+(4)^2

⇒ x=\sqrt{(3.6)^2+(4)^2}

⇒ x=\sqrt{12.96+16}

⇒ x=\sqrt{28.96}

⇒ x=5.38

Therefore , x=5.38 . Correct option C)5.38

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Step-by-step explanation:

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Step-by-step explanation:

I am not sure what it is asking, but if this is what you were asking for here it is. Surface area is harder to explain, but volume is multiply all dimensions.

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