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tester [92]
4 years ago
9

Which of the following is false

Mathematics
1 answer:
Margarita [4]4 years ago
6 0

Answer:

A

Step-by-step explanation:

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Help math<br><br> This is so confusing!
kari74 [83]

Answer:

0.2125 approximately 0.213

Step-by-step explanation:

6 divided by 5 is 0, u put ur point that is 0., then u add 0 to the 5 that makes it 50, 6 into 50 is 8 remaining 3 u add it to the 0. making it 0.8 then u add 0 to the 3 making it 30, 6 into 30 answer is 5. So u divide 0.85 divided by 4which is equal to 0.2125 approximately that is when u round up the last number when it is up to 5 which it is, it is equal to 0.213. I hope this is helpful for you

7 0
1 year ago
What is the future value of $1,600 in 17 years assuming an interest rate of 10 percent compounded semiannually?
Naddika [18.5K]
Let
F--------------------> future value
P--------------------> present value 
r --------------------> interest rate per year
m ------------------ > number of compounding periods per year
t -------------------->  time in years. 
we know that
P=$1,600
<span>t=17 years
m=2
r=10%------> 0.10

F=P(1+i)</span><span>^n
</span><span>where
i=r/m   ---------> 0.10/2=0.05
and
n=m*t------------> 2*17=34

</span>F=1600*(1+0.05)^34=8405.36
<span>
the answer is $</span>8405.36<span>

</span>
5 0
3 years ago
Use synthetic division to find (x^4-2x^3+x-9) / (x-2)
Mademuasel [1]
Set up the synthetic division using the coefficients of the numerator and the root in the denominator. Divide using the rules for synthetic division.
x^3 + 1 - 7 / x -2
Hope this helps! :)
5 0
4 years ago
the function g(t) = 2t represents the number of guitar lessons, g(t), you can complete in t months. how many guitar lessons can
Cloud [144]
T=months so if you have 7 months you would plug 7 in for (t)
making the equation g(7) = 2(7)
5 0
4 years ago
Hich function has a range of {y|y ≤ 5}?
marshall27 [118]

Answer:

f(x)=-(x-4)^{2}+5

Step-by-step explanation:

we know that

The equation of a vertical parabola into vertex form is equal to

y=a(x-h)^{2}+k

where

(h,k) is the vertex of the parabola

if a>0 -----> the parabola open upward (vertex is a minimum)

if a<0 -----> the parabola open downward (vertex is a maximum)

<u>Verify each case</u>

case A) f(x)=(x-4)^{2}+5

The vertex is the point (4,5)

a=1

a>0 -----> the parabola open upward (vertex is a minimum)

The range is the interval--------> [5,∞)

y\geq5

case B) f(x)=-(x-4)^{2}+5

The vertex is the point (4,5)

a=-1

a<0 -----> the parabola open downward (vertex is a maximum)

The range is the interval--------> (-∞,5]

y\leq 5

case C) f(x)=(x-5)^{2}+4

The vertex is the point (5,4)

a=1

a>0 -----> the parabola open upward (vertex is a minimum)

The range is the interval--------> [4,∞)

y\geq4

case D) f(x)=-(x-5)^{2}+4

The vertex is the point (5,4)

a=-1

a<0 -----> the parabola open downward (vertex is a maximum)

The range is the interval--------> (-∞,4]

y\leq 4

4 0
3 years ago
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