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ladessa [460]
3 years ago
13

PLEASE HELP!!!

Mathematics
1 answer:
IceJOKER [234]3 years ago
4 0

1. 3^4 x^3 z^2

2. 73 aabbbb

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Find the maximum walking speed of a coyote with legs 0.46 m long. How much faster can a giraffe walk than a coyote?
AfilCa [17]

Answer:

7.03 ft/s

Step-by-step explanation:

To obtain speed using the model :

Speed = sqrt(gL)

L = Length of leg, g = acceleration due to gravity

Length of leg of a giraffe = 6.03

g = 9.8 m/s or 32 ft/s²

Speed of giraffe in ft/s = sqrt(32 * 6.03) = 13.89 ft/ s

Speed of coyote ; L = 0.46 m

L in feets = 0.46 * 3.23 = 1.4858 feets

s = sqrt(1.4858 * 32) = 6.895 ft/s = 6.86 ft/s

Difference in speed :

13.89 - 6.86 = 7.03 ft/s

Giraffe has 7.03ft/s more speed Than a coyote

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3 years ago
A yardstick placed perpendicular to the ground casts a 4 foot shadow. At the same time, a grain silo casts a 34 foot shadow. Wri
kobusy [5.1K]
There is a 30 ft difference how can you not tell
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3 years ago
23 x 2<br><br> EZ question IK I’m just stoopid
mash [69]
It would be 46, have a nice day
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3 years ago
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In a certain region, the number of children who have been vaccinated against rubella is twice the number who have been vaccinate
MatroZZZ [7]

Answer:

C. 10 000

Step-by-step explanation:

If we called:

x = children who have been vacinated against rubella only

2x = children who have been vaccinated against mumps

y = children who have been vaccinated agains both

Children who have been vaccinated against mumps only = x - y

And we know that y = 2*(x-y)

=> 2y = 3x

y = 5000

There fore x = 7500

The number of children who have been vaccinated against rubella

= 2x - y = 2*7500 - 5000 = 15 000 - 5000 = 10 000

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3 years ago
In performing a chi-square goodness-of-fit test with multinomial probabilities, the ___________ the difference between observed
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Answer:

Step-by-step explanation:

The smaller/closer the difference between observed and expected frequencies, the higher the probability of concluding that the probabilities specified in the null hypothesis are correct concluding that the data fits that particular distribution given.

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4 years ago
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