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BlackZzzverrR [31]
3 years ago
6

2(3x+6) = 3(2x-6) solve equations with variables on both sides

Mathematics
1 answer:
Serjik [45]3 years ago
6 0
Answer:

2(3x+6) = 6x+12
3(2x-6) = 6x-18

6x+12=6x-18

Subtract 12 from 18, which gives you:

6x=6x-6

Subtract the 6x on the opposite side of the equal side, and your answer is: x = -6
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Where is the center of the circle and what is its radius
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Answer:

(3, -4) and r = 3

Step-by-step explanation:

The center of a circle can be found using the equation (x-h)^2 + (y-k)^2 = r^2 and is (h,k) from it. Notice h and k are the opposite value as in the equation.  

First write the equation in this form.  

x^2 - 6x + ( ?)+ y^2 +8y + (?) + 16 = 0  

Complete the square with each variable to find what numbers should go in place of the question marks.  

(-6/2)^2 = -3^2 = 9  

(8/2)^2 = 4^2 = 16  

Since 16 has already been added to the equation, just add 9 to both sides of the equation.  

x^2 - 6x + 9 + y^2 +8y + 16 = 9\\(x-3)^2 + (y+4)^2 = 9  

So the center is (3,-4) and the radius is 3.

5 0
3 years ago
Please help me?
lys-0071 [83]
<span>B. -6y = 12 is the asnwer</span>
4 0
3 years ago
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Step-by-step explanation:

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4 0
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1.<br> What is the solution of the system of equations?<br> y = 3x - 4<br> -3y = -9x + 12
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Answer:

Step-by-step explanation:

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