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Thepotemich [5.8K]
3 years ago
15

An inspection procedure at a manufacturing plant involves picking three items at random and then accepting the whole lot if AT L

EAST 2 of the three items are in perfect condition. If in reality 84% of the whole lot are perfect, what is the probability that the lot will be accepted?
Mathematics
1 answer:
aivan3 [116]3 years ago
5 0

Answer:

We use the Binomial Distribution   where p =.84 then probability will be 0.931.

Step-by-step explanation:

P(X≥ 2) = P(X=2) + P (X=3)

           = (³₂)(.84)^2(.16) +  (³3)(.84)^3(.16)⁰

           ≅ 0.931

Hence 0.931 is the answer.

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Y = -3x - 13<br> 9x - 2y = -4
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6

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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"Which ratio does not belong with the other three?" Explain your reasoning." Help me on 3. Please
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12:15 does not belong, since that is a ratio of 4:5, whilst the others are all 3:4.
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If x^2+y^2=1, what is the largest possible value of |x|+|y|?
Marianna [84]

If <em>x</em>² + <em>y</em>² = 1, then <em>y</em> = ±√(1 - <em>x</em>²).

Let <em>f(x)</em> = |<em>x</em>| + |±√(1 - <em>x</em>²)| = |<em>x</em>| + √(1 - <em>x</em>²).

If <em>x</em> < 0, we have |<em>x</em>| = -<em>x</em> ; otherwise, if <em>x</em> ≥ 0, then |<em>x</em>| = <em>x</em>.

• Case 1: suppose <em>x</em> < 0. Then

<em>f(x)</em> = -<em>x</em> + √(1 - <em>x</em>²)

<em>f'(x)</em> = -1 - <em>x</em>/√(1 - <em>x</em>²) = 0   →   <em>x</em> = -1/√2   →   <em>y</em> = ±1/√2

• Case 2: suppose <em>x</em> ≥ 0. Then

<em>f(x)</em> = <em>x</em> + √(1 - <em>x</em>²)

<em>f'(x)</em> = 1 - <em>x</em>/√(1 - <em>x</em>²) = 0   →   <em>x</em> = 1/√2   →   <em>y</em> = ±1/√2

In either case, |<em>x</em>| = |<em>y</em>| = 1/√2, so the maximum value of their sum is 2/√2 = √2.

6 0
3 years ago
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