Janine and her older sister Ingrid's ages are consecutive even numbers. When Janine's age is divided by seven, and Ingrid's age
is divided by three, the sum of those numbers is fourteen. How
old are Janine and Ingrid?
2 answers:
Answer:
Janine is 28. Ingrid is 30.
Step-by-step explanation:
Let the ages be x and x + 2 for Janine and her sister, respectively.
x/7 + (x + 2)/3 = 14
Multiply both sides by the LCD, 21, to get rid of denominators.
21 * x/7 + 21 * (x + 2)/2 = 21 * 14
3x + 7(x + 2) = 294
3x + 7x + 14 = 294
10x = 280
x = 28
x + 2 = 30
Answer: Janine is 28. Ingrid is 30.
Answer:
Janine is 28 and Ingrid is 30.
Step-by-step explanation:
Let Janine's age be x years , then Ingrid's age is x+2 years.
From the given information we have the equation:
x/7 + (x + 2)/3 = 14
Multiplying through by the LCM of 3 and 7 (21), we have:
3x + 7(x + 2) = 294
10x + 14 = 294
10x = 294-14 = 280
x = 28, so:
Janine is 28 and Ingrid is 30.
You might be interested in
They are 2015 and 2016.
divide 4031 by 2, and get rid of the decimal:
You will get 2015.
2015+2015 = 4030
2015+2016=4031
Answer:
See below and image
Step-by-step explanation:
180 + 48 = 228
180 + 55 = 235
Answer:
1] x=4.21
2] 52.5
3] 3.82
4] 38.73
5] 32.005
6] 31.21
Step-by-step explanation:
Above is postive. So the answer is +300
