First we can find the perimeter of the given rectangle
P=2L+2W (L=length and W=width)
P=2*3+2*4
P=6+8
P=14
So now we want to come up with a different combination of numbers that would give up a perimeter of 14. We know that 14 is divisible by 2 so let's make out width 2. If we plug in 2 as the width and 14 as the perimeters, we can solve for length
14=2L+2*2
14=2L+4
10=2L (subtract 4 from both sides)
L=5
So the dimensions are 5 units and 2 units
Hope this helps!
Answer:
<h2>
9</h2>
Step-by-step explanation:
The <u>square root </u>of
d=(x2−x1)^2+(y2−y1)^2
A=(2,5) coordinates 1
T=(5,5) coordinates 2
So we put (5-2)^2 plus (5-5)^2
(3)^2+(0)^2
9+0
9
<h3>
<u>Brainliest please!</u></h3>
Answer:

Step-by-step explanation:
We are given the function:

We want to find f(3), so we must substitute 3 in for x.

Solve according to PEMDAS: Parentheses, Exponents, Multiplication, Division, Addition, and Subtraction.
Solve the exponent first.

Multiply 8 and 3.

Add.

For the function given, f(3) is 30.