Janine and her older sister Ingrid's ages are consecutive even numbers. When Janine's age is divided by seven, and Ingrid's age

Question

3 years ago

14

is divided by three, the sum of those numbers is fourteen. How
old are Janine and Ingrid?

2 answers:

a_sh-v [17] · Answer 1 · 2022-08-22T03:25:31+03:00

Answer:

Janine is 28. Ingrid is 30.

Step-by-step explanation:

Let the ages be x and x + 2 for Janine and her sister, respectively.

x/7 + (x + 2)/3 = 14

Multiply both sides by the LCD, 21, to get rid of denominators.

21 * x/7 + 21 * (x + 2)/2 = 21 * 14

3x + 7(x + 2) = 294

3x + 7x + 14 = 294

10x = 280

x = 28

x + 2 = 30

Answer: Janine is 28. Ingrid is 30.

WINSTONCH [101] · Answer 2 · 2022-08-22T04:32:32+03:00

Answer:

Janine is 28 and Ingrid is 30.

Step-by-step explanation:

Let Janine's age be x years , then Ingrid's age is x+2 years.

From the given information we have the equation:

x/7 + (x + 2)/3 = 14

Multiplying through by the LCM of 3 and 7 (21), we have:

3x + 7(x + 2) = 294

10x + 14 = 294

10x = 294-14 = 280

x = 28, so:

Janine is 28 and Ingrid is 30.