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DiKsa [7]
4 years ago
15

Question 2 A sample of sodium chloride (NaCl) has a mass of 16.55 g.

Chemistry
2 answers:
Sliva [168]4 years ago
8 0

Explanation:

that was awesome thanks for this lovley question

Ivanshal [37]4 years ago
3 0

Answer:

Question2

A)<u>0.2832 moles NaCl</u>

<u>B) 0.2832 moles Na+ and 0.2832 moles Cl-</u>

<u>C) 1.7 * 10^23 Na+ atoms and 1.7 * 10^23 Cl- atoms</u>

<u />

<u>Question 3</u>

<u>A) </u>0.01587 moles sucrose

B) Number of moles carbon =  <u>0.1904 moles C</u>

Number of moles hydrogen = <u>0.3491 moles H</u>

Number of moles oxygen = <u>0.1746 moles O</u>

<u />

C) Number of atoms of carbon =  1.15 * 10^23 C atoms

Number of atoms of hydrogen = 2.1 * 10^23 H atoms

Number of atoms of oxygen = 1.05 *10^23 O atoms

Explanation:

Step 1: Data given

Molar mass of NaCl = 58.44 g/mol

A) Number of moles NaCl = 16.55 grams / 58.44 g/mol = <u>0.2832 moles NaCl</u>

B) Calculate number of moles Na+ and number of moles Cl-

NaCl → Na+ + Cl-

For 1 mol NaCl we have 1 mol of Na+ and 1 mol of Cl-

For 0.2832 moles NaCl we have <u>0.2832 moles Na+ and 0.2832 moles Cl-</u>

C) Calculate the number of atoms of Na+ and atoms of Cl-

Number of Na+ atoms = 6.022 * 10^23 / mol * 0.2832 moles = <u>1.7 * 10^23 Na+ atoms</u>

Number of Cl - atoms = 6.022 * 10^23 / mol * 0.2832 moles = <u>1.7 * 10^23 Cl- atoms</u>

Question 3

A) Calculate the number of moles of C12H22O11 in the sample.

Moles sucrose = mass / molar mass

Moles sucrose = 5.432 grams / 342.3 g/mol = 0.01587 moles

B) A sample of table sugar (sucrose, C12H22O11) has a mass of 5.432 g. Calculate the number of moles Carbon. Calculate the number of moles Hydrogen. Calculate the number of moles Oxygen.

In 1 mol C12H22O11 we have 12 moles of carbon, 22 moles of hydrogen and 11 moles of oxygen

Number of moles carbon = 12 * 0.01587 moles = <u>0.1904 moles C</u>

Number of moles hydrogen = 22 * 0.01587 moles = <u>0.3491 moles H</u>

Number of moles oxygen = 11 * 0.01587 = <u>0.1746 moles O</u>

C)  A sample of table sugar (sucrose, C12H22O11) has a mass of 5.432 g. Calculate the number of atoms Carbon. Calculate the number of atoms Hydrogen. Calculate the number of atoms Oxygen.

Number of atoms of carbon = 6.022 *10^23 /mol *  0.1904 moles = 1.15 * 10^23 C atoms

Number of atoms of hydrogen = 6.022 * 10^23 / mol * 0.3491 moles = 2.1 * 10^23 H atoms

Number of atoms of oxygen = 6.022*10^23 / mol * 0.1746 moles = 1.05 *10^23 O atoms

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Explanation:

Step 1: data given

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Step 2: The balanced equation

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Step 3: Calculate the limiting reactant

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Volume of oxygen required = ?

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There are 7 moles of oxygen = 7×22.414 = 156.9 L

Now we will compare the litters of water and oxygen:

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                              134.5         :              156.9

                                77.4         :             156.9/134.5×77.4 =90.3 L

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