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Kay [80]
2 years ago
10

5) Which of the elements have a charge of 2-, as determined by their locations on

Chemistry
1 answer:
Galina-37 [17]2 years ago
5 0
The metals one column to the right of the first have a charge of 2-. This is due to the element having an extra electron in comparison to the number of neutrons.
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How many electrons will each element gain or lose in forming an ion?
Amanda [17]
It depends on the number of valence electrons required to make octet or duplet( in case of H). For example, Nitrogen(atomic number = 7) has electronic configuration(2,5) which means nitrogen has 5 valence electrons and requires 3 more electrons to complete its octet. After gaining 3 electrons from atoms of an element with less electronegativity than N, it forms nitride ion (N ^{-3}). Hope this helps.
8 0
3 years ago
I just don’t know what to do
ValentinkaMS [17]

Answer:

I dont know if this is correct.. but maybe in the tool row, put graduated cylinder because you use graduated cylinders to measure water and for units put milliliters or liters?? Sorry if this isnt correct i wouldnt know what else to put !

Explanation:

3 0
2 years ago
hich of the following is TRUE? Group of answer choices A neutral solution does not contain any H3O+ or OH- A neutral solution co
Studentka2010 [4]

Answer:

a basic solution has [OH-] > [H3O+]

8 0
3 years ago
Determine the density of a liquid from the following data: Mass of the
Tanya [424]

Answer:0.477 g/ml

Explanation:

Density=(40.14-33.79)/13.3 ml

Density=6.35/13.3

Density=0.477 g/ml

6 0
2 years ago
Separate a mixture of sand, common salt, copper pieces and iron fillings. Also measure the amount of common salt in the mixture.
Neporo4naja [7]

Answer:

Explanation:

This question seeks to test the knowledge of separation techniques.

From the narration in the question, the first separation to be done is the removal of Iron fillings by the use of magnet (magnetic separation). Since Iron is magnetic, the iron fillings will be attracted by the magnet hence removing the iron fillings from the mixture.

The second constituent to be removed will be the copper pieces by the use of a sieve (sieving). Copper pieces have relatively larger sizes than sand and common salt, hence a sieve (which separates particles based on size) can be used to remove the copper pieces from the mixture.

What will be left in the mixture after the processes above will be salt and water. This mixture will have to be dissolved in water; the salt will dissolve in water while the sand will not. After which, filtration will be done to remove the sand which will be collected on the filter paper as filtride and the salt solution will pass through the filter paper as filtrate.

The salt solution can then be evaporated to dryness to retrieve the solid salt from the solution.

The amount of salt in the mixture can then be measured using a weighing balance.

Some of safety measures to be taken during the course of this experiment includes performing the experiment in an airtight and controlled environment. Lab coat and hand gloves should be worn during the course of the experiment. The evaporation to dryness should not be done close to an inflammable material/substance

5 0
3 years ago
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