Answer:
2.01 x 103 mm Hg
Explanation:
To convert from atmospheres to millimeters of mercury, it is necessary to know the equivalence between the two units (1 atm = 760.0 mm Hg). The atmosphere units should be arranged to cancel out in order to obtain units in millimeters of mercury.
We need to separate different components of a mixture to separate the useful components from the non-useful or some harmful components.
Examples:
(a) Tea leaves are separated from tea.
(b) Pebbles are separated form rice and pulse.
Explanation:
Because two sides don't have an equal number of O atoms. The left side has 6 O atoms (3*2) while the right side has only 1 O atom. to balance the equation, you need an equal number of atoms on both sides.
<u>Answer:</u> 1.2 moles of carbon dioxide is produced for the given value of oxygen.
<u>Explanation:</u>
The chemical reaction for the combustion of acetylene follows the equation:

By stoichiometry of the reaction:
5 moles of oxygen produces 4 moles of carbon dioxide.
So, 1.5 moles of oxygen will produce =
of carbon dioxide.
Hence, 1.2 moles of carbon dioxide is produced for the given value of oxygen.
The mass of I₂ that contains 2.57×10²⁵ molecules is 10843.52 g
From a detailed understanding of Avogadro's hypothesis, we understood 1 mole of any substance contains 6.02×10²³ molecules. This implies that 1 mole of I₂ also 6.02×10²³ molecules i.e
<h3>6.02×10²³ molecules = 1 mole of I₂</h3>
Recall:
1 mole of I₂ = 2 × 127 = 254 g
Thus,
<h3>6.02×10²³ molecules = 254 g of I₂</h3>
With the above information, we can obtain the mass of I₂ that contains 2.57×10²⁵ molecules. This is illustrated below:
6.02×10²³ molecules = 254 g of I₂
Therefore,
2.57×10²⁵ molecules = 
<h3>2.57×10²⁵ molecules = 10843.52 g of I₂</h3>
Thus, the mass of I₂ that contains 2.57×10²⁵ molecules is 10843.52 g
Learn more: brainly.com/question/24848191