Step-by-step explanation:
> 2×2a²×2a²
8a⁴
> 36a³×1/4a²
9a³×1/a²
9a
> 2⁶
> 5²m²
Given

subject to the constraint

Let

.
The gradient vectors of

and

are:

and

By Lagrange's theorem, there is a number

, such that


It can be seen that

has local extreme values at the given region.
Answer:
False B=1
Step-by-step explanation:
10b+18=28
Subtract 18 both sides.
10b=10
Divide 10 both sides.
b=1
Answer:
31.5 or 63/2
Step-by-step explanation:
to do this, first you need to transform the <u>mixed number</u> <em>(3 1/2)</em> into an <u>improper fraction</u>, to get 7/2.
then you just multiply 9 by 7/2
9/1 (7/2)
63/2 = 31.5
<em>both of the answers in bold are correct</em>