Question

Calculate the molarity of a solution of acetic acid made by dissolving 16.00 mL of glacial acetic acid at 25 ∘C in enough water to make 230.0 mL of solution.

Answer 1

Answer : The molarity of solution is, 1.216 g/mole

Explanation : Given,

Density of acetic acid = 1.049 g/ml  (standard value)

Volume of acetic acid = 16.00 ml

Volume of solution = 230.0 ml

Molar mass of acetic acid $CH_3COOH$ = $2(12)+4(1)+2(16)=60g/mole$

First we have to calculate the mass of acetic acid.

$Mass=Density\times Volume$

$Mass=1.049g/ml\times 16ml=16.784g$

Now we have to calculate the molarity of solution.

$Molarity=\frac{\text{Mass of acetic acid}\times 1000}{\text{Molar mass of acetic acid}\times \text{volume of solution in ml}}$

$Molarity=\frac{16.784g\times 1000}{60g/mole\times 230ml}$

$Molarity=1.216g/mole$

Therefore, the molarity of solution is, 1.216 g/mole