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swat32
3 years ago
8

A puppy weighs 12 ounces. What fractional part of a pound is this?

Mathematics
2 answers:
ExtremeBDS [4]3 years ago
8 0

Hello,

The correct answer is 3/4

Because 3 × 4 = 12

Hope this helps!!!! Happy Holidays!!!! (:

labwork [276]3 years ago
4 0
The puppy is 3/4 of a pound.

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sasho [114]

The type of government where the president and its Congress weer controlled by the same party is one which is democratic and has such specific laws.

<h3>What is a System of Government?</h3>

This refers to the different ways in which a sovereign nation makes its laws and also makes policies that affects its citizens.

There are different systems of government and some of them includes:

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brainly.com/question/26100096

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2 years ago
What is an integer?
Digiron [165]

Answer:

B

Step-by-step explanation:

An integer is any whole number (both positive and negative) and zero.

5 0
3 years ago
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The given matrix is the augmented matrix for a linear system. Use technology to perform the row operations needed to transform t
shtirl [24]

Answer:

x_{1} = \frac{176}{127} + \frac{71}{127}x_{4}\\\\ x_{2} = \frac{284}{127} + \frac{131}{254}x_{4}\\\\x_{3} = \frac{845}{127} + \frac{663}{254}x_{4}\\

Step-by-step explanation:

As the given Augmented matrix is

\left[\begin{array}{ccccc}9&-2&0&-4&:8\\0&7&-1&-1&:9\\8&12&-6&5&:-2\end{array}\right]

Step 1 :

r_{1}↔r_{1} - r_{2}

\left[\begin{array}{ccccc}1&-14&6&-9&:10\\0&7&-1&-1&:9\\8&12&-6&5&:-2\end{array}\right]

Step 2 :

r_{3}↔r_{3} - 8r_{1}

\left[\begin{array}{ccccc}1&-14&6&-9&:10\\0&7&-1&-1&:9\\0&124&-54&77&:-82\end{array}\right]

Step 3 :

r_{2}↔\frac{r_{2}}{7}

\left[\begin{array}{ccccc}1&-14&6&-9&:10\\0&1&-\frac{1}{7} &-\frac{1}{7} &:\frac{9}{7} \\0&124&-54&77&:-82\end{array}\right]

Step 4 :

r_{1}↔r_{1} + 14r_{2} , r_{3}↔r_{3} - 124r_{2}

\left[\begin{array}{ccccc}1&0&4&-11&:-8\\0&1&-\frac{1}{7} &-\frac{1}{7} &:\frac{9}{7} \\0&0&- \frac{254}{7} &\frac{663}{7} &:-\frac{1690}{7} \end{array}\right]

Step 5 :

r_{3}↔\frac{r_{3}. 7}{254}

\left[\begin{array}{ccccc}1&0&4&-11&:-8\\0&1&-\frac{1}{7} &-\frac{1}{7} &:\frac{9}{7} \\0&0&1&-\frac{663}{254} &:-\frac{1690}{254} \end{array}\right]

Step 6 :

r_{1}↔r_{1} - 4r_{3} , r_{2}↔r_{2} + \frac{1}{7} r_{3}

\left[\begin{array}{ccccc}1&0&0&-\frac{71}{127} &:\frac{176}{127} \\0&1&0&-\frac{131}{254} &:\frac{284}{127} \\0&0&1&-\frac{663}{254} &:\frac{845}{127} \end{array}\right]

∴ we get

x_{1} = \frac{176}{127} + \frac{71}{127}x_{4}\\\\ x_{2} = \frac{284}{127} + \frac{131}{254}x_{4}\\\\x_{3} = \frac{845}{127} + \frac{663}{254}x_{4}\\

6 0
3 years ago
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GrogVix [38]

point slope form

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change to slope intercept form

y-9 = 2(x-1)

distribute

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add 9 to each side

y = 2x-2+9

y = 2x+7

4 0
3 years ago
Read 2 more answers
What is the slope of the line containg (-2,5) and (4,-4)​
Zanzabum

Answer:

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Step-by-step explanation:

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