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vagabundo [1.1K]
3 years ago
10

Which represents a side length of a square that has an area of 450 square inches?

Mathematics
1 answer:
amm18123 years ago
5 0

The formula of an area of a square:


A=a^2


a - a side


We have A=450\ in^2


substitute:


a^2=450\to a=\sqrt{450}\\\\a=\sqrt{225\cdot2}\\\\a=\sqrt{225}\cdot\sqrt2\\\\\boxed{a=15\sqrt2\ in}


Used:

\sqrt{a\cdot b}=\sqrt{a}\cdot\sqrt{b}

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Find an ordered pair that is solution for linear equation 4x-5y=20​
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Answer:

(5,0) is the solution of the given equation.

(0,-4) is the solution of the given equation.

Step-by-step explanation:

Here, the given equation is: 4 x- 5y  = 20

Now, we need to find a value for (x,y) such that the above equation is satisfied.

The ONLY POSSIBLE way to do this is Hit and Trial.

Let us substitute x  = 0

Then the equation becomes : 4 (0) - 5y = 20

or, -5 y =  20 ⇒  y = -20/5 = - 4

So, for x = 0, y = - 4

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or, 4 x =  20 ⇒  x = 20/4 = 5

So, for x = 5, y = 0

So, (5,0) will be the solution of the given equation.

We can try another substitution as well.

For any value of x, we will get a corresponding value of y. So, (x,y) will be the solution of the given equation.

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What is the area of the rhombus? 10 km 7 km​
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Answer:

A=pq

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Not sure if i got this right?
aleksandrvk [35]

Answer:

The effect it will have on the volume is;

The volume will be 8 times larger

Step-by-step explanation:

The dimensions of the given prism are;

The length of the prism, l = 5 in.

The breadth of the prism, b = 5 in.

The slant height of the prism,  = 4 in. by 5 in.

The height of the prism, h = 7 in.

The shape of the prism = Parallelepiped

The volume of a parallelepiped = Area of Base × Height of the prism

The base area of the parallelepiped = The length × Breadth of the parallelepiped

∴ The base area of the given parallelepiped = 5 in. × 5 in. = 25 in.²

The volume of the given parallelepiped, V₁ is found as follows;

V₁ = 5 in. × 5 in. × 7 in. = 25 in.² × 7 in. = 175 in.³

When a scale factor of 2 in applied to the dimensions of the prism, we have;

The new volume, V₂ =  2 × 5 in. × 2 × 5 in. × 2 × 7 in.

∴ V₂ = 2 × 2 × 2 × 5 in. × 5 in. × 7 in. = 8 × 5 in. × 5 in. × 7 in. = 8 × V₁

Therefore;

V₂ = 8 × V₁

The volume of the image of the object, V₂ after applying a scale factor of 2 is 8 times larger than the volume of the object, V₁.

5 0
3 years ago
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