$12 = 3.4 = 3 .2.2 = 3.2^{2}\\12^{3} = (3.2^{2} )^{3} = 3^{3}2^{6} \\6 = 3.2\\6^{5} = (3.2)^{5} = 3^{5} .2^{5} \\\\Numerator = 3^32^63^52^5 = 3^82^{11}\\Denominator computation\\9 = 3^2\\9^{4} = (3^{2} )^4 = 3^{8} \\Denominator = 3^82^{10} \\\\\frac{Numerator}{Denominator } =\frac{{3^8}{2^{11} }}{3^82^{10}} = \frac{2^{11}} {2^{10}} = 2^1 = 2$

7 0

2 years ago

3. Given that ∆RSV - ∆RTU, find the coordinates of S and the scale factor. R(0, 0) T(16,0) V(0, --6) U(0, -8)

MArishka [77]

Answer:

I'll give the scale factor and you can compute the coordinates of S

Step-by-step explanation:

the dilation if centered about the origin is the scale factor multiplied by each coordinate.

so looking at points V and U, the scale factor F is found by solving for F:

-6xF= -8

F=8/6=4/3

Now you can compute the coordinates for S

send a comment if you need help

5 0

3 years ago

What is 16-2t = t + 9 + 4t

Semmy [17]

Answer:

t=1

Step-by-step explanation:

16-2t = t + 9 + 4t

Combine like terms

16-2t = 9 + 5t

Add 2t to each side

16 -2t+2t = 9+5t+2t

16 = 9+7t

Subtract 9 from each side

16-9 = 9-9 +7t

7=7t

Divide each side by 7

7/7 = 7t/7

1 =t

6 0

3 years ago

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