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DENIUS [597]
3 years ago
5

A packet contains 10 sweets.

Mathematics
2 answers:
erastova [34]3 years ago
8 0

Answer:Am nevoie de Puncte

Step-by-step explanation:

vagabundo [1.1K]3 years ago
4 0

For 2 people, you can give 5 to one, and 5 to the other, equally split from 10

For 3 people, you can give each person 3 whole candies, and 1/3 of the remaining 1 candy that is left to split between three people (3 tiny pieces for the 3 people

And for 4 people, you can give each one 2 whole candies, and 1/2 of the remaining candies to all four people (2 candies, when split in half is 4 in total) !!

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Sofia bought a tablet that was 15 % off the regular price of $775.
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Answer: $698.275

Step-by-step explanation:

$(775 x (85/100)) x 106/100

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Q1 Write the number in expanded form for the significant digits ( as fractions)
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Find the mistake <br> 3(x-6)+(4x+12)-6x=<br> 3x-9+4x+12-6x=<br> (3x+4x-6x)+(-9+12)=<br> x+3
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Q.6. The equation of the ellipse whose centre is at the origin and the x-axis, the major axis, which passes
azamat

<h3>Answer:</h3>

Equation of the ellipse = 3x² + 5y² = 32

<h3>Step-by-step explanation:</h3>

<h2>Given:</h2>

  • The centre of the ellipse is at the origin and the X axis is the major axis

  • It passes through the points (-3, 1) and (2, -2)

<h2>To Find:</h2>

  • The equation of the ellipse

<h2>Solution:</h2>

The equation of an ellipse is given by,

\sf \dfrac{x^2}{a^2} +\dfrac{y^2}{b^2} =1

Given that the ellipse passes through the point (-3, 1)

Hence,

\sf \dfrac{(-3)^2}{a^2} +\dfrac{1^2}{b^2} =1

Cross multiplying we get,

  • 9b² + a² = 1 ²× a²b²
  • a²b² = 9b² + a²

Multiply by 4 on both sides,

  • 4a²b² = 36b² + 4a²------(1)

Also by given the ellipse passes through the point (2, -2)

Substituting this,

\sf \dfrac{2^2}{a^2} +\dfrac{(-2)^2}{b^2} =1

Cross multiply,

  • 4b² + 4a² = 1 × a²b²
  • a²b² = 4b² + 4a²-------(2)

Subtracting equations 2 and 1,

  • 3a²b² = 32b²
  • 3a² = 32
  • a² = 32/3----(3)

Substituting in 2,

  • 32/3 × b² = 4b² + 4 × 32/3
  • 32/3 b² = 4b² + 128/3
  • 32/3 b² = (12b² + 128)/3
  • 32b² = 12b² + 128
  • 20b² = 128
  • b² = 128/20 = 32/5

Substituting the values in the equation for ellipse,

\sf \dfrac{x^2}{32/3} +\dfrac{y^2}{32/5} =1

\sf \dfrac{3x^2}{32} +\dfrac{5y^2}{32} =1

Multiplying whole equation by 32 we get,

3x² + 5y² = 32

<h3>Hence equation of the ellipse is 3x² + 5y² = 32</h3>
8 0
3 years ago
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