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3 years ago

HELP ME PLEASE ASAP

2 answers:

6 0

All you have to do is make a equation. Which would be p5+3 =v the answer should be 8 because if you plug 8 in you get (8)5+3=v 40+3= 43 then you add 8 to 43 and get 51 so i believe the answer to your question is 8

ratelena [41]3 years ago

6 0

Answer: There are 8 pepperoni pizzas she order.

Step-by-step explanation:

Since we have given that

Number of vegetable pizzas and pepperoni pizzas for the eighth grade party = 51

Let the number of pepperoni pizzas be 'p'.

Let the number of vegetable pizzas be 'v'.

According to question,

$v=5p+3$

So, it becomes,

$v+p=51\\\\5p+3+p=51\\\\6p+3=51\\\\6p=51-3\\\\6p=48\\\\p=\dfrac{48}{6}\\\\p=8$

Hence, there are 8 pepperoni pizzas she order.

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Need help ASAP !!!<br><br><img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B88%20%5Ctimes%2011%20%5Ctimes%202%20%5Ctimes%204%7D%20"

Elina [12.6K]

Answer:

√(88×11×2×4}=√88²=±88 is your answer

3 0

3 years ago

Read 2 more answers

Seven hundred twelve thousandths in expanded form

matrenka [14]

(7×100)+(0.001×12) = 700.012

Hope It Helps :]

3 0

3 years ago

Determine whether the graph represents a proportional relationship.

Alexus [3.1K]

Answer:

No, it is not a proportional relationship because the graph does not go through the origin

Step-by-step explanation:

it has to go through zero as in the (origin)

4 0

2 years ago

Solve for m<br>2m = -6n -5; n = 1, 2 ,3

rosijanka [135]

Substitute with the value of n in the equation to get m as follows:
at n=1:
2m=-6(1)-5=-6-5=-11
m = -11/2
at n=2:
2m=-6(2)-5=-12-5=-17
m = -17/2
at n=3:
2m=-6(3)-5=-18-5=-23
m = -23/2

8 0

3 years ago

a parabola has an x-intercept at 2, its axis of symmetry is the line x=4, and the y-coordinate of its vertex is 6. Determine the

nlexa [21]

Answer:

The standard equation of the parabola is:

$y=-\frac{3}{2}x^2+12x-18$

Step-by-step explanation:

An x intercept of 2 means that the point (2, 0) is in the graph of the parabola.

We can also write the general expression for the parabola in vertex form, since we can use the information on the coordinates of the vertex: (4, 6) - recall that the axis of symmetry of the parabola goes through the parabola's vertex, so the x-value of the vertex must be x=4.

$y-y_{vertex}=a\,(x-x_{vertex})^2\\y-6=a\,(x-4)^2$

Now we can find the value of the parameter "a" by using the extra information about the point (2, 0) at which the parabola intercepts the x-axis:

$y-6=a\,(x-4)^2\\0-6=a\,(2-4)^2\\-6=a\,4\\a=-\frac{6}{4} =-\frac{3}{2}$

Then the equation of the parabola becomes:

$y-6=-\frac{3}{2} \,(x-4)^2\\y-6=-\frac{3}{2} (x^2-8x+16)\\y-6=-\frac{3}{2}x^2+12x-24\\y=-\frac{3}{2}x^2+12x-18$

7 0

3 years ago