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Arturiano [62]
4 years ago
7

What is the volume of this rectangular prism? 4/3 4/3 4/3

Mathematics
1 answer:
Leokris [45]4 years ago
7 0

Answer:

\frac{64}{27} cm³

Step-by-step explanation:

The volume (V) of the prism is calculated as

V = lbh ( l is length, b is breadth and h is height ), thus

V = \frac{4}{3} × \frac{4}{3} × \frac{4}{3} = \frac{4^3}{3^3} = \frac{64}{27} cm³

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What is the period of the function y= 3/2 cot(3/5x) +5?
finlep [7]

Answer:

D; 5pi/3 units

Step-by-step explanation:

Here, we want to find the period of the function;

y = 3/2 cot (3/5x) + 5

By definition, the period of a function is the interval between two matching points in the function.

Let’s say it is the distance between two peaks, crests, etc on a function.

To find the value of the period. We shall standardize the function.

What this means is that we shall be writing the function in the standard form.

The standard form is as follows;

f(x) = A trig(Bx -C) + D

Where trig refers to the accompanying trigonometric function in question.

Comparing this standard form with our question, we can see that;

A is 3/2

B is 3/5

C is 0

D is 5

Now for cot and tan functions, we shall need to divide pi by the absolute value of B

Thus we have; pi divided by 3/5 which gives 5pi/3 units

7 0
3 years ago
family of solutions of the second-order DE y y 0. Find a solution of the second-order IVP consisting of this differential equati
Anna35 [415]

Answer:

y = \frac{1}{2}e^x -\frac{1}{2} e^{2-x}

Step-by-step explanation:

Given

y=c_1e^x +c_2e^{-x

y(1) = 0

y'(1) =e

Required

The solution

Differentiate y=c_1e^x +c_2e^{-x

y' = c_1e^x - c_2e^{-x}

Next, we solve for c1 and c2

y(1) = 0 implies that; x = 1 and y = 0

So, we have:

y=c_1e^x +c_2e^{-x

0 = c_1 * e^1 + c_2 * e^{-1}

0 = c_1 e + \frac{1}{e}c_2 --- (1)

y'(1) =e implies that: x = 1 and y' = e

So, we have:

y' = c_1e^x - c_2e^{-x}

e = c_1 * e^1 - c_2 * e^{-1}

e = c_1 e - \frac{1}{e}c_2 --- (2)

Add (1) and (2)

0 + e = c_1e + c_1e + \frac{1}{e}c_2 - \frac{1}{e}c_2

e = 2c_1e

Divide both sided by e

1 = 2c_1

Divide both sides by 2

c_1 = \frac{1}{2}

Substitute c_1 = \frac{1}{2} in 0 = c_1 e + \frac{1}{e}c_2

0 = \frac{1}{2} e+ \frac{1}{e}c_2

Rewrite as:

\frac{1}{e}c_2 = -\frac{1}{2} e

Multiply both sides by e

c_2 = -\frac{1}{2} e^2

So, we have:

y=c_1e^x +c_2e^{-x

y = \frac{1}{2}e^x -\frac{1}{2} e^2 * e^{-x}

y = \frac{1}{2}e^x -\frac{1}{2} e^{2-x}

6 0
3 years ago
What is 5/16 in if the scale is 1 in=8ft?
Sonbull [250]
2.5 hopefully this helpsss
8 0
4 years ago
Which is not a part or budget?
8_murik_8 [283]

Answer:

I think D.

Step-by-step explanation:

Depending on the feasibility of these estimates, Budgets are of three types -- balanced budget, surplus budget and deficit budget. Depending on the feasibility of these estimates, budgets are of three types -- balanced budget, surplus budget and deficit budget.

7 0
3 years ago
Two schools had a track and field competition. One school took 3,784 students. The other school
kati45 [8]

Answer:

4527

Step-by-step explanation:

total amount students = 4527+1641

=6168

amount of students who did not win a medal = total - amount who won a medal

= 6168-1641

=4527

3 0
4 years ago
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