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ch4aika [34]
3 years ago
11

A. Yesterday, Kelly went to the Sea Animal Park on a class trip. The Sea Animal Park had a total of 3,840 visitors for the first

3 weeks of the month. There were 1,368 visitors the first week and 1,277 visitors the second week. What was the number of visitors for the third week? Show your work.
B. During the first 3 weeks, 18 buses full of stừdents visited the Sea Animal Park. Each bus had 54 students. What is the total number of students that visited the Sea Animal Park during the 3 weeks? Explain how you found your answer.

C. Yesterday, on Kelly's class trip, 4 groups of 52 students visited the Sea Animal Park. The students attended a special dolphin show in which they were able to pet the dolphins. The students were placed in groups, with 7 students in each group. Kelly used division to find the total number of groups that were needed so that each student was able to pet the dolphins. She said that a total of 29 groups were needed. Did Kelly correctly solve the division problem? Why or why not? ​
Mathematics
1 answer:
jolli1 [7]3 years ago
5 0

Answer:

1195

Step-by-step explanation: add the first 2 weeks and then subtract them from the total visitors

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PLEASE ANSWER ASSAP!!! IF CORRECT WILL GIVE BRAINLY!!!!! Which one of these relationships is different than the other three? Exp
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Answer:

The relationship B is different than the other three, because it has a different proportionality constant.

Step-by-step explanation:

All available options show direct relationships, which are defined as follows:

y\propto x

y=k\cdot x (1)

Where:

x - Independent variable, dimensionless.

y - Dependent variable, dimensionless.

k - Proportionality constant, dimensionless.

We proceed to use the following strategy based on the proportionality constant, that is:

k = \frac{y}{x}

A different relationship must indicate a different proportionality constant:

Option A (x = 0.8, y = 4)

k = \frac{4}{0.8}

k = 5

Option B (x = 10, y = 55)

k = \frac{55}{10}

k = 5.5

Option C (x = 4, y = 20)

k = \frac{20}{4}

k = 5

Option D (x = 10, y = 50)

k = \frac{50}{10}

k = 5

The relationship B is different than the other three, because it has a different proportionality constant.

3 0
3 years ago
In a​ region, 90​% of the population have brown eyes. If 15 people are randomly​ selected, find the probability that at least 13
Andrew [12]

Answer:

a) P(X \geq 13) = P(X=13) +P(X=14) +P(X=15)

P(X=13)=(15C13)(0.9)^{13} (1-0.9)^{15-13}=0.267  

P(X=14)=(15C14)(0.9)^{14} (1-0.9)^{15-14}=0.343  

P(X=15)=(15C15)(0.9)^{15} (1-0.9)^{15-15}=0.206  

And replacing we got:

P(X \geq 13) = P(X=13) +P(X=14) +P(X=15)=0.267+0.343+0.206=0.816

b) D. No​, because the probability of this occurring is not small.

Step-by-step explanation:

Previous concepts  

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".  

Part a

If 15 people are randomly​ selected, find the probability that at least 13 of them have brown eyes.

Let X the random variable of interest, on this case we now that:  

X \sim Binom(n=15, p=0.90)  

The probability mass function for the Binomial distribution is given as:  

P(X)=(nCx)(p)^x (1-p)^{n-x}  

Where (nCx) means combinatory and it's given by this formula:  

nCx=\frac{n!}{(n-x)! x!}  

And we want to find this probability:

P(X \geq 13) = P(X=13) +P(X=14) +P(X=15)

P(X=13)=(15C13)(0.9)^{13} (1-0.9)^{15-13}=0.267  

P(X=14)=(15C14)(0.9)^{14} (1-0.9)^{15-14}=0.343  

P(X=15)=(15C15)(0.9)^{15} (1-0.9)^{15-15}=0.206  

And replacing we got:

P(X \geq 13) = P(X=13) +P(X=14) +P(X=15)=0.267+0.343+0.206=0.816

Part b

Is it unusual to randomly select 15 people and find that at least 13 of them have brown​ eyes? Note that a small probability is one that is less than 0.05.

Since our calculated probability is too higher compared to 0.05 we can conclude this:

D. No​, because the probability of this occurring is not small.

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Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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3 years ago
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