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melamori03 [73]
3 years ago
14

PLEASE HELP I DON'T KNOW HOW TO DO THIS

Mathematics
1 answer:
TEA [102]3 years ago
3 0
I think the answer is between-5 to 10
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Find the area of a triangle bounded by the y-axis, the line
Pepsi [2]
The area is 68.47.

A drawing of the triangle is attached.

We first plot the y-intercept of the line given to us, f(x)=34-4x.  This is in the form f(x)=mx+b, so the y-intercept, b, is 34.  

Next we use the slope to find the next points of the line.  The slope is -4, which can be written as -4/1 (rise/run).  This means from the y-intercept, we go down 4 and over 1 to plot the next point, and continue in this manner.  We now have the y-axis and this line drawn.

Next we use the slope of the line to find the slope of the perpendicular line described.  Two lines are perpendicular if their slopes are negative reciprocals of each other.  The slope of the first line was -4/1; this means the slope of this line must be 1/4.  We also know this point goes through the origin, so 0 is the y-intercept, and we have the equation f(x)=1/4x+0.

To graph this, plot a point at 0, the y-intercept.  The slope is 1/4, so we go up 1 and over 4 to the next point.  This happens to be on the line we previously drew.

To find the area of this triangle, we need to identify the base and height.  The height will be perpendicular to the base.  The two sides that form a right angle are the bottom and the right hand side, so the bottom is the base and the right hand side is the height.

Now we find the length of each of these sides using the distance formula.  For the height:

d=\sqrt{(y_2-y_1)^2+(x_2-x_1)^2}=\sqrt{(34-1)^2+(0-4)^2}
\\
\\=\sqrt{33^2+(-4)^2}=\sqrt{1089+16}=\sqrt{1105}\approx33.24

To find the length of the base:
d=\sqrt{(0-1)^2+(0-4)^2}=\sqrt{(-1)^2+(-4)^2}=\sqrt{1+16}=\sqrt{17}
\\
\\\approx4.12

The area of a triangle is given by A=1/2bh:
A=1/2(33.24)(4.12) = 68.4744 ≈ 68.47

5 0
3 years ago
How do I solve 20? Thanks
Gnom [1K]
20)

using
<span>a^3 + b^3 = (a+b)(a^2 − ab + b^2)
</span>so
w^3 + 125z^3
= w^3 +(5z)^3
= (w + 5z)(w^2 - 5wz + 25z^2)

hope it helps
6 0
4 years ago
A polynomial function has a root of –3 with multiplicity 2, a root of 0 with multiplicity 1, a root of 1 with multiplicity 1, an
Ratling [72]

Answer:

The first graph picture

Step-by-step explanation:

A polynomials is an equation with many terms whose leading term is the highest exponent known as degree. The degree or exponent tells how many roots exist. These roots are the x-intercepts.

This polynomial has roots -3, 0, 1, and 3. This means the graph must touch or cross through the x-axis at these x-values. What determines if it crosses the x-axis or the simple touch it and bounce back? The even or odd multiplicity - how many times the root occurs.

In this polynomial:

Root -3 has even multiplicity of 2 so it only touches and does not cross through.

Root 0 has odd multiplicity of 1 so crosses through.

Root 1 has odd multiplicity of 1 so crosses through.

Root 3 has even multiplicity of 3 so it only touches and does not cross through.

Knowing this, only the first and second graphs are possible answers.

Lastly, what determines the facing of the graph (up or down) is the leading coefficient. If positive, the graph ends point up. If negative, the graph ends point down. All even degree graphs will have this shape.

Only graph 1 matches the features of this polynomial.

8 0
3 years ago
Read 2 more answers
Solve for x<br> 3xy=w<br><br> please help
san4es73 [151]

Answer

x= w/3y

Step-by-step explanation:

to isolate x you divide each side by 3y, which results in x= w/3y

: )

5 0
3 years ago
Read 2 more answers
Six times the sum of a number<br> and two is 30. Find the number
Airida [17]
3 because 3 + 2= 5 n 5*6=30
6 0
3 years ago
Read 2 more answers
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