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2 years ago

Can someone help me answer these questions

Mathematics

1 answer:

Vlad1618 [11]2 years ago

4 0

We can't see the questions from this picture of you show a picture that we can see or type the answers we can answer

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8 is to 32 as 9 is to N? What is N?

kodGreya [7K]

36, 8 times 4 is 32. After figuring that 4 is the multiple, you would multiply 9 by 4 giving you the N.

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2 years ago

Which relation is not a function? Reporting wrong answers.

Aleks [24]

Answer:

C im pretty sure dont report me tho

Step-by-step explanation:

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2 years ago

The 5 in 6.052 has 1/10 the value of the 5 in _____? a)0.815 b)53.2 c)4.45 d)7.5

olasank [31]

Would it be a correct me if im wrong

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3 years ago

Find the sum of the equation

stealth61 [152]

Answer:

$\frac{{y}^{2}+13y-6}{{(y-1)}^{2}(y+7)}$

Step-by-step explanation:

1) Rewrite ${y}^{2}-2y+1y$ in the form ${a}^{2}-2ab+{b}^{2}$ , where a = y and b = 1.

$\frac{y}{{y}^{2}-2(y)(1)+{1}^{2}}+\frac{6}{{y}^{2}+6y-7}$

2) Use Square of Difference: ${(a-b)}^{2}={a}^{2}-2ab+{b}^{2}$ .

$\frac{y}{{(y-1)}^{2}}+\frac{6}{{y}^{2}+6y-7}$

3) Factor ${y}^{2}+6y-7$ .

1 - Ask: Which two numbers add up to 6 and multiply to -7?

-1 and 7

2 - Rewrite the expression using the above.

$(y-1)(y-7)$

Outcome/Result: $\frac{y}{(y-1)^2} +\frac{6}{(y-1)(y+7)}$

4) Rewrite the expression with a common denominator.

$\frac{y(y+7)+6(y-1)}{{(y-1)}^{2}(y+7)}$

5) Expand.

$\frac{{y}^{2}+7y+6y-6}{{(y-1)}^{2}(y+7)}$

6) Collect like terms.

$\frac{{y}^{2}+(7y+6y)-6}{{(y-1)}^{2}(y+7)}$

7) Simplify ${y}^{2}+(7y+6y)-6y$ to ${y}^{2}+13y-6y$

$\frac{{y}^{2}+13y-6}{{(y-1)}^{2}(y+7)}$

5 0

2 years ago

Read 2 more answers

If there are 120 calories in 4 ounces of hot fudge, how many calories are in 8

miss Akunina [59]

Answer:

240 calories

Step-by-step explanation

You're doubling the amount of fudge, so double the amount of calories. You could also think of it as 2 4-oz portions of fudge, then just add the calories (120+120) together.

3 0

3 years ago