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2 years ago

1. Dr. Stats plans to toss a fair coin 10,000 times in the hope that it will lead him to a deeper

Mathematics

2 answers:

lisov135 [29]2 years ago

6 0

Answer: D

Step-by-step explanation:

A- You cannot judge experimental probabilities by theoretical probabilities. Experiments will not show the exact, calculated probabilities.

B- Previous events do not impact the probability of future events. It's still 50/50

C- See B.

D- The theoretical probability for heads is 50%. The experimental probability will not be EXACTLY 50%, but ABOUT 50%, like this option explains

ankoles [38]2 years ago

3 0

Answer:

No matter what the odds would be 50% just like the odds of a kid being a boy for example so the right answer is D.

Step-by-step explanation:

You might be interested in

Money Flow The rate of a continuous money flow starts at $1000 and increases exponentially at 5% per year for 4 years. Find the

77julia77 [94]

Answer:

Present value = $4,122.4

Accumulated amount = $4,742

Step-by-step explanation:

Data provided in the question:

Amount at the Start of money flow = $1,000

Increase in amount is exponentially at the rate of 5% per year

Time = 4 years

Interest rate = 3.5% compounded continuously

Now,

Accumulated Value of the money flow = $1000e^{0.05t}$

The present value of the money flow = $\int\limits^4_0 {1000e^{0.05t}(e^{-0.035t})} \, dt$

= $1000\int\limits^4_0 {e^{0.015t}} \, dt$

= $1000\left [\frac{e^{0.015t}}{0.015} \right ]_0^4$

= $1000\times\left [\frac{e^{0.015(4)}}{0.015} -\frac{e^{0.015(0)}}{0.015} \right]$

= 1000 × [70.7891 - 66.6667]

= $4,122.4

Accumulated interest = $e^{rt}\int\limits^4_0 {1000e^{0.05t}(e^{-0.035t}} \, dt$

= $e^{0.035\times4}\times4,122.4$

= $4,742

8 0

2 years ago

A Galapagos cactus finch population increases by half every decade. The number of finches is

Angelina_Jolie [31]

Answer:

The number of fringes at $d=-2$ is given as 20.

Step-by-step explanation:

Question

A Galapagos cactus finch population increases by half every decade. The number of finches is modeled by the expression

where d is the number of decades after the population was measured. Evaluate the expression for d = −2

Given :

The number of finches is modeled by the expression :

⇒ $45\cdot1.5^d$

where $d$ is the number of decades after the population was measured.

To evaluate the expression for d=-2

Solution:

In order to evaluate the given expression to find the number of finches at $d=-2$ , we will plugin $-2$ for $d$ in the expression and simplify it.

Plugging in $d=-2$ in the expression:

⇒ $45\cdot 1.5^{-2}$

Using negative exponent property. [ $a^{-x}=\frac{1}{a^x}$

⇒ $45\cdot \frac{1}{1.5^2}$

⇒ $45\cdot \frac{1}{2.25}$

⇒ $20$ (Answer)

Thus, the number of fringes at $d=-2$ is given as 20.

This means the number of fringes two decades ago was 20.

6 0

2 years ago

A factory makes 1200 shirts every 6 hours.the factory makes shirts for 9 hours a workday. what is the fewest number of workdays

Dominik [7]

1. Divide the target number of shirts, 12,600 by the company's rate of making the shirts. That is,
number of hours = 12,600 shirts/ (1200 shirts/6 hours)
= 63 hours
2. Determine the number of workdays for them to complete the shirts by dividing 63 hours by 9 hours/workday. This will give us an answer of 7 workdays.

8 0

2 years ago

No more chocolate or transporters

Goryan [66]

Answer:

thats absolutely right

5 0

2 years ago

Read 2 more answers

choli [55]

Answer: B.x^3+4x^2-19x+14 is correct

Step-by-step explanation:

(x + 7)(x2 – 3x + 2)

Multiplying both

x^3-3x^2+2x+7x^2-21x+14

x^3+4x^2-19x+14

7 0

2 years ago