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beks73 [17]
3 years ago
9

Apply the distributive property to factor out the greatest common factor. 250-150x =

Mathematics
1 answer:
Savatey [412]3 years ago
7 0

Answer:

50(5 - 3x)

Step-by-step explanation:

The given expresion is

250 - 150x

The greatest common factor is 50.

We rewrite using the distributive property to get;

50 \times 5- 50 \times 3xWe collect the highest common factor to obtain:

50(5 - 3x)

Therefore when we factor out the greatest common factor from the given expresion we get;

50(5 - 3x)

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What is the product? (x 3)(2 x minus 1) 2 x squared minus 3 2 x squared 6 x 2 x squared 5 x minus 3 2 x squared 6 x minus 3.
prohojiy [21]

The product of the function is 2x^2+ 5x - 3

We are to find the product of the functions x + 3 and 2x -1

  • let f(x) = x+ 3
  • g(x) = 2x - 1

Taking the product:

f(x)g(x) = (x+3)(2x -1)

f(x)g(x) = x(2x) - x(1) + 3(2x) + 3(-1)

f(x)g(x) = 2x^2 - x + 6x - 3

f(x)g(x) = 2x^2+ 5x - 3

Hence the product of the function is 2x^2+ 5x - 3

Learn more on product of functions here: brainly.com/question/25638609

5 0
2 years ago
What is the correct evaluation of 3x2 + 4x - 2y2 + 4y + 5, when x is equal to -1 and y is equal to 5?
Julli [10]
3x2+4(-1)-2(5)2 +4(5)+5=
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31-14=17
8 0
3 years ago
URGENT!!! Please answer ASAP with full working out thank you
Tema [17]

Step-by-step explanation:

a) \\  \frac{a}{x - 1}  -  \frac{2}{x + 1}  =  \frac{4}{(x - 1)(x + 1)}  \\  \\  \frac{a(x + 1) - 2(x - 1)}{(x  -  1)(x + 1)} =  \frac{4}{(x - 1)(x + 1)}  \\  \\ a(x + 1) - 2x + 2 = 4 \\  \\ a(x + 1) = 4 + 2x - 2 \\  \\ a(x + 1) = 2x + 2 \\  \\ a (x + 1) = 2(x + 1) \\  \\ a= \frac{2(x + 1)}{(x + 1)}  \\  \\  \huge \red{ \boxed{a = 2}}

Solve b part yourself in the same way.

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3 years ago
How to solve a math equation step by step
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Where is the problem?
7 0
3 years ago
Read 2 more answers
A car requires 22 litres of petrol to travel a distance of 259.6 km.Find
Anon25 [30]

Answer:

Step-by-step explanation:

1. A car requires 22 litres of petrol to travel a distance of 259.6 km

what is the distance that the car can travel on 63 ltr of petrol

22ltr = 259.6km

63ltr=

cross multiply

{63 x 259.6}/22 = 16354.8/22 = 743.4 km

A car requires 22 litres of petrol to travel a distance of 259.6 km, it would require 63 ltr of petrol to travel 743.4km

2. To travel a distance of 2013.2 km

we would need to calculate the amount of fuel

A car requires 22 litres of petrol to travel a distance of 259.6 km

what amount of fuel would it require to travel 2013.2km

22ltr = 259.6km

xltr = 2013.2km

x is the value of petrol to cover 2013.2km

cross multiply

(2013.2 x 22)/259.6

44290.4/259.6 = 170.610169492≈170.6 ltr

A car requires 22 litres of petrol to travel a distance of 259.6 km, it would require 170.6 ltr of petrol to travel 2013.2km

if 1ltr is $1.99

170.6 ltr is (170.6 x 1.99)/1 = $339.494≈$339.5

The price of fuel consumed for 2013.2 km at 1 liter of petrol at $1.99 is $339.5

5 0
2 years ago
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