The question is incomplete, here is the complete question:
The half-life of a certain radioactive substance is 46 days. There are 12.6 g present initially.
When will there be less than 1 g remaining?
<u>Answer:</u> The time required for a radioactive substance to remain less than 1 gram is 168.27 days.
<u>Step-by-step explanation:</u>
All radioactive decay processes follow first order reaction.
To calculate the rate constant by given half life of the reaction, we use the equation:
where,
= half life period of the reaction = 46 days
k = rate constant = ?
Putting values in above equation, we get:
The formula used to calculate the time period for a first order reaction follows:
where,
k = rate constant =
t = time period = ? days
a = initial concentration of the reactant = 12.6 g
a - x = concentration of reactant left after time 't' = 1 g
Putting values in above equation, we get:
Hence, the time required for a radioactive substance to remain less than 1 gram is 168.27 days.
Answer:
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Answer:
3.5 feet.
Step-by-step explanation:
r=C/2π
r=22/2π
r=22/6.28
r≈3.5
Answer:
3 1/3 miles per hour
Step-by-step explanation:
(5/2 ÷ 3/4) = (s ÷1)
(5/2 ÷ 3/4) = 10/3
10/3 = s/1
cross-multiply:
3s = 10
s = 10/3
s = 3 1/3 miles per hour
Answer:
Yo my guy, this is really easy
Step-by-step explanation: