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stira [4]
3 years ago
15

You need to strengthen a 19% alcohol solution with pure alcohol solution to obtain 40% solution. How much pure alcohol should yo

u add to 100 milliliters of the 19% solution.
Can anyone solve this problem???
Mathematics
1 answer:
Alex73 [517]3 years ago
8 0
Let x be the number of mm of pure alcohol to be added:

I will add the mm to express the volume in mm
100mm.(19%) + (100%).x mL = (100 mL+x mL).(40%).
Now right again without the %
100.(0.19) + x.(1) = (100+x).(0.4)

19 + x = = 40 + 04x
x - 0.4x = 40 - 19
0.6 x = 21
x = 21/0.6  and x = 35 mL. This te quantity of pure alcohol should to be added to get a solution at 40%.



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