Discriminant = b^2 - 4ac, where a, b and c come from the form of the quadratic equation as ax^2 + bx + c
Discriminant = (4)^2 - 4(1)(5)
= 16 - 20
= -4
-4 < 0, therefor there are no roots
(If the discriminant = 0, then there is one root
If the discriminant > 0, there are two roots, and if it is a perfect square (eg. 4, 9, 16, etc.) then there are two rational roots
If the discriminant < 0, there are no roots)
PEMDAS
P- none
E- none
M- none
D- (3/1/3=1)
AS- 9-1+1=9
The answer is A.
For this case we have the following function:
By definition, we have that a linear equation is of the form 
On the other hand, a quadratic equation is of the form
Then, the given equation is not a linear equation, it is not of the form
Answer:
No, the equation is not linear. It is not of the form 
Answer: 9/14
Explanation. First, you have to find the least common denominator. The least common denominator is the lowest number you can use on the denominator to create a set of equivalent fractions
7 and 2 can both go into 14
Whatever number you use to multiply to equal 14, you do the same to the top.
It would look like this.
2/14 + 7/14
Then you add.
2/14 + 7/14= 9/14
You can’t simplify this fraction so this is your answer. Hope this helped!
