Assuming that <span>4^2-6(2^x)-16=0 is correct, we can rearrange it as:
</span><span>-6(2^x) + 4^2 - 16=0
Are you sure it's not </span>6(2^x) + 4^2 - 16=0 ?
If 6(2^x) + 4^2 - 16=0 is correct, then
6(2^x) + 4^2 - 16=16 - 16 = 0, that is, 6(2^x) = 0. Then x = 0 (answer)
Answer: The answer would be A. 5
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Answer:
if 
is divided by 
, the remainder is -9
Step-by-step explanation:
We need to find the remainder if is divided by
Dividing by
The division is shown in figure attached.
The remainder = -9
The quotient = x+3
So, if is divided by , the remainder is -9
R(x) = 60x - 0.2x^2
The revenue is maximum when the derivative of R(x) = 0.
dR(x)/dx = 60 - 0.4x = 0
0.4x = 60
x = 60/0.4 = 150
Therefore, maximum revenue is 60(150) - 0.2(150)^2 = 9000 - 4500 = $4,500
Maximum revenue is $4,500 and the number of units is 150 units
"14,494 rounded to the nearest ten-thousands" would be 10,000.
Because the value of the digit before the ten thousands place (4) is less than the value of 5, the digit in the ten-thousands position does not change.
