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sashaice [31]
3 years ago
8

The vertex of parabola is (2,-2) Another point on the parabola is (5,7). find another point on the parabola.

Mathematics
1 answer:
ehidna [41]3 years ago
8 0

Answer:(4,-2)


Step-by-step explanation: on the graph you can see the 4 and the -2 put to point on the 4 to the -2 and you get your answer


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4^2-6(2^x)-16=0<br><br><br>solve for x
ahrayia [7]
Assuming that   <span>4^2-6(2^x)-16=0   is correct, we can rearrange it as:

</span><span>-6(2^x) + 4^2 - 16=0

Are you sure it's not   </span>6(2^x) + 4^2 - 16=0  ?

If   6(2^x) + 4^2 - 16=0    is correct, then

6(2^x) + 4^2 - 16=16 - 16 = 0, that is,   6(2^x) = 0.  Then x = 0 (answer)
8 0
3 years ago
Substitute 9 for x and evaluate the expression below. (x-1) -3 A, 5 B, 7 C 11 D, 13
Sphinxa [80]

Answer: The answer would be A. 5

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6 0
3 years ago
Complete the following statement.
Svetradugi [14.3K]

Answer:

if p ( x ) = x^2 + 7 x + 3 is divided by x + 4, the remainder is -9

Step-by-step explanation:

We need to find the remainder if p ( x ) = x^2 + 7 x + 3 is divided by x + 4

Dividing p ( x ) = x^2 + 7 x + 3 by x + 4

The division is shown in figure attached.

The remainder = -9

The quotient = x+3

So, if p ( x ) = x^2 + 7 x + 3 is divided by x + 4, the remainder is -9

3 0
3 years ago
A manufacturer finds that the revenue generated by selling x units of a certain commodity is given by the function R(x) = 60x −
bonufazy [111]
R(x) = 60x - 0.2x^2

The revenue is maximum when the derivative of R(x) = 0.
dR(x)/dx = 60 - 0.4x = 0
0.4x = 60
x = 60/0.4 = 150

Therefore, maximum revenue is 60(150) - 0.2(150)^2 = 9000 - 4500 = $4,500
Maximum revenue is $4,500 and the number of units is 150 units
7 0
3 years ago
Read 2 more answers
14,494 ten thousand round to
SVETLANKA909090 [29]

"14,494 rounded to the nearest ten-thousands" would be 10,000.

Because the value of the digit before the ten thousands place (4) is less than the value of 5, the digit in the ten-thousands position does not change.

3 0
3 years ago
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