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Elodia [21]
3 years ago
7

Simplify using appropriate identity 0.85 × 0.85 +2 × 0.85 ×0.15 × 0.15

Mathematics
2 answers:
spayn [35]3 years ago
7 0

The answer is <u><em>0.76075</em></u>!

<em>Hope this helps!</em>

guapka [62]3 years ago
4 0

Remember that multiplication is to be done before addition or subtraction.  We see that both terms have the factor 0.85:

0.85 × 0.85 +2 × 0.85 ×0.15 × 0.15 =

0.85 * ( 0.85 + 2*0.15*0.15).  

This is equivalent to 0.85 ( 0.85 + 2*0.0225 ) = 0.85 ( 0.895 ).

This last result could be left as is, or evaluated with a calculator:

0.76075

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Step-by-step explanation:

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If ΔABC is similar to ΔDEF, the m∠A = 50 degrees, and m∠E = 70 degrees, what is m∠C?
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Point M is on line segment \overline{LN}
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Point M splits line LN into two parts, LM and MN, hence the total length is given by:

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1 year ago
​(A) How many ways can a 3​-person subcommittee be selected from a committee of 6 ​people? ​(B) How many ways can a president co
Zepler [3.9K]

Answer:

A) N = 20 ways

a 3​-person subcommittee can be selected from a committee of 6 ​people in 20 ways.

B)N = 120 ways

The president, vice president and secretary can be chosen from a committee of 6 ​people in 120 ways.

Step-by-step explanation:

A) the number of ways a 3​-person subcommittee be selected from a committee of 6 ​people N;

Since there is no given order for the selection, this means that the order of selection is irrelevant. Therefore, this is a combination problem where order is not considered.

N = nCr

N = 6C3

N = 6!/3!(6-3)! = 6!/3!3!

N = 720/(6×6)

N = 20 ways

a 3​-person subcommittee can be selected from a committee of 6 ​people in 20 ways.

B) the number of ways a president, vice president and secretary can be chosen from a committee of 6 ​people N;

In this case, there is a given order of selection for the 3 posts. This is a permutation.

N = nPr

N = 6P3

N = 6!/(6-3)!

N = 6!/3!

N = 120 ways

The president, vice president and secretary can be chosen from a committee of 6 ​people in 120 ways.

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