All categories

3 years ago

What is the solution of 7^3x = 400?

Mathematics

2 answers:

Mazyrski [523]3 years ago

7 0

X= 400/343 simplify each side of the equation and isolate the variable

OlgaM077 [116]3 years ago

6 0

Hi,
$7^{3x}=400\\\\

3x*ln(7)=ln(400)\\\\

x= \dfrac{ln(400)}{3*ln(7)} \\\\

x =1,026334566...
\\x\approx 1.03$

You might be interested in

an alloy of tin is 15% tin weigh 20 pounds . A second alloy is 10% tin . how much pounds of the second alloy must be added to th

Ulleksa [173]

12%=(3+10%*x)/(20+x)
x=30

add 30 pounds of the second alloy

7 0

2 years ago

A number is equal to twice a smaller number plus 3. The same number is equal to twice the sum of the smaller number and 1. How m

erma4kov [3.2K]

There are no solutions for this situation. =)

3 0

2 years ago

Read 2 more answers

Section 5.2 Problem 17:

Elina [12.6K]

This DE has characteristic equation

$4r^2 - 12r + 9r = (2r - 3)^2 = 0$

with a repeated root at r = 3/2. Then the characteristic solution is

$y_c = C_1 e^{\frac32 x} + C_2 x e^{\frac32 x}$

which has derivative

${y_c}' = \dfrac{3C_1}2 e^{\frac32 x} + \dfrac{3C_2}2 x e^{\frac32x} + C_2 e^{\frac32 x}$

Use the given initial conditions to solve for the constants:

$y(0) = 3 \implies 3 = C_1$

$y'(0) = \dfrac52 \implies \dfrac52 = \dfrac{3C_1}2 + C_2 \implies C_2 = -2$

and so the particular solution to the IVP is

$\boxed{y(x) = 3 e^{\frac32 x} - 2 x e^{\frac32 x}}$

8 0

2 years ago

A one-parameter family of solutions of the de p' = p(1 − p) is given below.

tensa zangetsu [6.8K]

Answer:

A solution curve pass through the point (0,4) when $c_{1} = -\frac{4}{3}$ .

There is not a solution curve passing through the point(0,1).

Step-by-step explanation:

We have the following solution:

$P(t) = \frac{c_{1}e^{t}}{1 + c_{1}e^{t}}$

Does any solution curve pass through the point (0, 4)?

We have to see if P = 4 when t = 0.

$P(t) = \frac{c_{1}e^{t}}{1 + c_{1}e^{t}}$

$4 = \frac{c_{1}}{1 + c_{1}}$

$4 + 4c_{1} = c_{1}$

$c_{1} = -\frac{4}{3}$

A solution curve pass through the point (0,4) when $c_{1} = -\frac{4}{3}$ .

Through the point (0, 1)?

Same thing as above

$P(t) = \frac{c_{1}e^{t}}{1 + c_{1}e^{t}}$

$1 = \frac{c_{1}}{1 + c_{1}}$

$1 + c_{1} = c_{1}$

$0c_{1} = 1$

No solution.

So there is not a solution curve passing through the point(0,1).

3 0

3 years ago

Write the expanded form of the expression. 7(2x + y)

MAVERICK [17]

Answer:

14x+7y

Step-by-step explanation:

7 0

2 years ago