I hope this helps you
cos71=15/P
0.325=15/P
P=46.15
Answer:
y = 5x -15
Step-by-step explanation:
slope/y-int from = y =mx+b
slope = y2-y1/x2-x2
slope = 0--15 / 3-0
slope = 15 / 3
slope = 5
y-int = -15
y = 5x-15
Sedimentary rocks for the first one I think
Answer:
The amount of heat required to raise the temperature of liquid water is 9605 kilo joule .
Step-by-step explanation:
Given as :
The mass of liquid water = 50 g
The initial temperature =
= 15°c
The final temperature =
= 100°c
The latent heat of vaporization of water = 2260.0 J/g
Let The amount of heat required to raise temperature = Q Joule
Now, From method
Heat = mass × latent heat × change in temperature
Or, Q = m × s × ΔT
or, Q = m × s × (
-
)
So, Q = 50 g × 2260.0 J/g × ( 100°c - 15°c )
Or, Q = 50 g × 2260.0 J/g × 85°c
∴ Q = 9,605,000 joule
Or, Q = 9,605 × 10³ joule
Or, Q = 9605 kilo joule
Hence The amount of heat required to raise the temperature of liquid water is 9605 kilo joule . Answer
Answer:
m<Q = 30 degrees
Step-by-step explanation:
Add 126 and 24 which equals 150
Subtract 180 from 150
You get 30