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alisha [4.7K]
3 years ago
10

What is the greatest common factor of 10, 20, and 50?

Mathematics
1 answer:
Viefleur [7K]3 years ago
6 0

Answer:

10

Step-by-step explanation:

first you need to find the prime factors of the three numbers

ex:

prime factor of 18= 2*3*3

prime of 24=2*2*2*3

there is one 2 and one 3 in common

greatest common multiple 2*3=6

so the greatest common multiple is ten because it is the only one that can divide between all three evenly.

10=10/10=1\\20=20/10=2\\50=50/10=5

so 10 is your answer

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Which should be the first step in solving the equation 1.2w-3.8=12.4
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Answer:

+3.8 to each side

Step-by-step explanation:

8 0
3 years ago
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Lisa collected leaves from different trees for a science project. Every day for a week (7 days), she collected 7 leaves. How man
tangare [24]

Answer:

49 leaves

Step-by-step explanation:

7 days x 7 leaves per day = 49 leaves in total

6 0
1 year ago
Suppose the diameter of a circle is 6 units What is its circumference?
Kipish [7]

Answer:

18.84 estimated, 6π exactly

Step-by-step explanation:

Hi!

<u>The formula for finding the circumference of a circle is 2πr:</u>

In that case, all we need to do <em>first </em>is to divide the diameter by 2, so we can substitute that into the equation.

6 ÷ 2 = 3

So we have 2π × 3 to solve.

2π × 3 = 6π

We can estimate the circumference by multiplying by 3.14.

6 × 3.14 = 18.84

(actually multiplying by π gives 18.849... which is pretty close!)

Thus, the circumference is \boxed{6\pi{\text{\:or\:18.84\:roughly}}}.

Hope this helps!

6 0
3 years ago
CAN SOMEONE PLEASE HELP ME PLEASE help
strojnjashka [21]

Answer:

I got uuuuu

Step-by-step explanation:

Here you go

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3 0
3 years ago
The perimeter of a rectangle is 42 inches, and its area is 110 square inches. find the length and width of the rectangle.
lorasvet [3.4K]
p = 2w + 2l              p = 42 
a = l * w                   a = 108

You want to make either the length or width variable (I chose the width variable to be by itself. It doesn't matter) by itself by:

Divide both sides by 2.
(p) ÷ 2 = (2w + 2l) ÷ 2 
               2's  cancel  out
\frac{p}{2} = w + l

Subtract both sides by either length or width depending on what variable you chose to make by itself (in this case I subtracted the length variable because I wanted the width variable by itself).
\frac{p}{2} - l = w + l - l
                 l's  cancel  out 
p/2 - l = w

a = l * w

You replace w with the equation above p/2 - l = w 
a = l( \frac{p}{2} - l)

Multiply out the L.
a = \frac{p}{2}l - l^{2}

Plug in all your numbers a = 110 and p = 42
110 = \frac{42}{2}l - l^{2}
110 = 21l - l^{2

Move everything to the left side so l^{2} would be positive (makes the equation easier when l^{2} is positive).
l^{2} - 21l + 110 = 0

Factor.
(l -10)(l-11) = 0

Make each parenthesis set equal to 0.
l-11=0     l-10=0

Add.
l = 11  l = 10

By doing this you solve for both the width and length so the answer is:
w = 11    L = 10
8 0
3 years ago
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