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Dafna11 [192]
3 years ago
11

Six years from today you need $10,000. you plan to deposit $1,500 annually, with the first payment to be made a year from today,

in an account that pays an 8% effective annual rate. your last deposit, which will occur at the end of year 6, will be for less than $1,500 if less is needed to reach $10,000. how large will your last payment be?
Mathematics
1 answer:
Novosadov [1.4K]3 years ago
3 0
Like this variation of the problem! :)

We calculate the future value of the 6 annual deposits of $1500 at 8%:
F=1500(1.08^6-1)/(0.08)=11003.89
Since the last payment is due on the day of withdrawal, he would have paid $1500 to get back $11003.89, i.e. with an excess of 1003.89.
Therefore his last payment is 1500-1003.89=$496.11
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Iteration - Maths Question attached
Ivanshal [37]

Answer:

7.8

Step-by-step explanation:

First I will try 50. I got 127,550, so that was way too big.

Let me try a smaller number. How about 5. I got 155, so that was a bit too small.

Now I'll try 20. I got 8420. Looks like the number is between 5 and 20.

How about 7. I got 399.

Let me try 8. I got 584! That's really close. It's just a little too big.

I tried 7.5, and got 485.624. So close! Just a little higher.

Putting in 7.8 yields <u>543.192!</u> That's our answer.

8 0
3 years ago
Whats is 2400000 in standard form
Ghella [55]
The best answer would be 
2.4 x 10 ^6
10 to the sixth power multiplied by 2.4
7 0
3 years ago
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my friend and i made balls of snow all morning. by night fall we had build 13 snowmen. how many balls of snow did we make​
Zigmanuir [339]

Answer:

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Step-by-step explanation:

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4 0
3 years ago
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Let f(x)=4x-1 and g(x)=2x^2+3. Perform each function operations and then find the domain.
Triss [41]
F(x) = 4x - 1
g(x) = 2x² + 3

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    (f + g)(x) = 2x² + 4x + 2
    Domain: {x| -∞ < x < ∞}, (-∞, ∞)

2. (f - g)(x) = (4x + 1) - (2x² + 3)
    (f - g)(x) = 4x + 1 - 2x² - 3
    (f - g)(x) = -2x² + 4x + 1 - 3
    (f - g)(x) = -2x² + 4x - 2
    Domain: {x|-∞ < x < ∞}, (-∞, ∞)
3. (g - f)(x) = (2x² + 3) - (4x - 1)
    (g - f)(x) = 2x² + 3 - 4x + 1
    (g - f)(x) = 2x² - 4x + 3 + 1
    (g - f)(x) = 2x² - 4x + 4
    Domain: {x| -∞ < x < ∞}, (-∞, ∞)

4. (f · g)(x) = (4x + 1)(2x² + 3)
    (f · g)(x) = 4x(2x² + 3) + 1(2x² + 3)
    (f · g)(x) = 4x(2x²) + 4x(3) + 1(2x²) + 1(3)
    (f · g)(x) = 8x³ + 12x + 2x² + 3
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    Domain: {x| -∞ < x < ∞}, (-∞, ∞)

5. (\frac{f}{g})(x) = \frac{4x - 1}{2x^{2} + 3}
    Domain: 2x² + 3 ≠ 0
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                        2x² ≠ 0
                         2      2
                          x² ≠ 0
                           x ≠ 0
                  (-∞, 0) ∨ (0, ∞)

6. (\frac{g}{f})(x) = \frac{2x^{2} + 3}{4x - 1}
    Domain: 4x - 1 ≠ 0
                      + 1 + 1
                        4x ≠ 0
                         4     4
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6 0
3 years ago
Consider the formula for the slope between two coordinates
krek1111 [17]

The following equations is equivalent to the slope formula is A) y₂= m(x₂-x₁) + y₁.

<h3>What is slope?</h3>

The angle of inclination of a line with respect to the horizontal is quantified. In analytical geometry, a line, ray, or line segment's slope is the proportion of the vertical to the horizontal distance between any two points ("slope equals rise over run").

<h3>What is equation?</h3>

Two expressions are combined by the equal sign to form a mathematical statement known as an equation. For instance, a formula might be 3x - 5 = 16. We discover that the variable x has a value of 7 after solving this equation.

Given that,

Take a look at the formula below for the slope between two coordinate locations, m.

m = \frac{y_{2}- y_{1} }{x_{2}-x_{1}  }

Here, slope is

m = \frac{y_{2}-y_{1}  }{x_{2}-x_{1}  }

Where m is the slope and y₁ and y₂ and x₁ and x₂ are coordinates of the axis.

The first step is to multiply x₂-x₁ on both sides in order to acquire y₂ on its own.

so you must add y₁ to both sides in order to get y₂ alone.

m(x₂-x₁) +y₁ = y₂.

Therefore, the following equations is equivalent to the slope formula is A) y₂ = m(x₂-x₁) + y₁.

To know more about the slope, visit:

brainly.com/question/16508963

#SPJ9

5 0
1 year ago
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