Answer:
z1 + z2 = 3
Step-by-step explanation:
Since we are given z1 = 2 + √(3)i and z2 = 1 – √(3)i. The sum of z1 + z2 would be:
(2 + √(3)i) + (1 – √(3)i) = 2 + √(3)i + 1 – √(3)i = 2 + 1 + √(3)i – √(3)i = 3
Hence, z1 + z2 = 3.
Answer:
m=2 and n=3
Step-by-step explanation:
<u>Step</u> :-
Given ![[ 2 x^{n}y^{2} ]^m = 4 x^6 y^4](https://tex.z-dn.net/?f=%5B%202%20x%5E%7Bn%7Dy%5E%7B2%7D%20%5D%5Em%20%3D%204%20x%5E6%20y%5E4)
using algebraic formula 
now

now equating 'x' powers, we get

....(1)
now

Equating 'y' powers ,we get
2 m=4
m=2
substitute m= 2 in equation (1)
we get
2 n=6
n=3
verification:-
substitute m=2 and n=3 , we get
![[ 2 x^{n}y^{2} ]^m = 4 x^6 y^4](https://tex.z-dn.net/?f=%5B%202%20x%5E%7Bn%7Dy%5E%7B2%7D%20%5D%5Em%20%3D%204%20x%5E6%20y%5E4)


both are equating so m= 2 and n=3
Answer:
the answer is 60045
Step-by-step explanation:
the answer is 60000 because 6×10=60×100=60000+45=60045
Answer:
The box-and-whisker plot for the given question is as shown at the attached figure.
Minimum = 11
Lower quartile = Q1 = 12
Median = Q2 = 23.5
Upper quartile = Q3 = 27
Maximum = 33
<u>So, according to the given data and the figure:</u>
- The box will go from <u>12 to 27</u> ⇒ Q1 to Q3
- A line dividing the box will go at <u>23.5</u> ⇒ Q2
- The left whisker will go from <u>11 to 12</u> ⇒ Minimum to Q1
- The right whisker will go from to <u>27 to 33</u> ⇒ Q2 to Maximum