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o-na [289]
3 years ago
10

Andrew drew a square with each side measuring 3 inches. Lindsay drew a triangle with each side measuring 4 inches. Which shape h

as a greater​ perimeter? Write an equation to help explain your answer.
Select the correct answer​ below, and fill in the answer boxes to complete your choice.
​(Use the operation symbols in the math palette as​ needed.)
A.
The square has a greater perimeter of
nothing inches. An equation for the perimeter of the shapes is
nothing.
B.
The triangle has a greater perimeter of
nothing inches. An equation for the perimeter of the shapes is
nothing.
C.
Both shapes have a perimeter of
nothing inches. An equation for the perimeter of the shapes is
nothing.
Mathematics
2 answers:
fredd [130]3 years ago
5 0
C is the correct answer
jok3333 [9.3K]3 years ago
3 0

Answer:

C.

Both shapes have a perimeter of

12 inches. An equation for the perimeter of the shapes is 3 + 3 + 3 + 3 = 4 + 4 + 4.

Step-by-step explanation:

Since a square has 4 sides, we need to multiply 3 by 4 which is 12. Since a triangle has 3 sides, we need to multiply 4 by 3 which is 12. Therefore, both shapes share the same perimeter.

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The area of a rectangle is 44m2. Work out the missing length x.
Shalnov [3]

Answer:

Your answer is

How to determine length without width or other things.

11*4,,,

22*2

Want more answer then follow me, like and MARK MY ANSWER AS BRAINLIST ANSWER.

I need that urgently.

5 0
2 years ago
Read 2 more answers
Suppose a regular n-gon is inscribed in a circle of radius r. Diagrams are shown for n=6, n=8, and n = 12. n = 6 n=8 n = 12 a a
m_a_m_a [10]

Answer:If an N-gon (polygon with N sides) has perimeter P, then each of the  

N sides has length P/N.  If we connect two adjacent vertices to the  

center, the angle between these two lines is 360/N degrees, or 2*pi/N  

radians.  (Do you understand radian measure well enough to follow me  

this far?)

The two lines I just drew, plus the side of the polygon between them,  

form an isosceles triangle.  Adding the altitude of the isosceles  

triangle makes two right triangles, and we can use one of them to  

derive the equation

 sin(theta/2) =  s/(2R)

where theta is the apex angle (which I said is 2*pi/N radians), R is  

the length of the lines to the center (the radius of the circumscribed  

circle), and s is the length of the side (which I said is P/N).

Putting those values into the equation, we have

 sin(pi/N) = P/(2NR)

so that

 P = 2NR sin(pi/N)

gives the perimeter of the N-gon with circumradius R.

Can we see a connection between this formula and the perimeter of a  

circle?  The perimeter of the circumcircle is 2*pi*R.  As we increase  

N, the perimeter of the polygon should get closer and closer to this  

value.  Comparing the two, we see

 2NR*sin(pi/N) approaches 2*pi*R

 N*sin(pi/N)   approaches pi

You can check this out with a calculator, using big numbers for N such  

as your teacher's N=1000.  If you calculate the sine of an angle in  

degrees rather than radians, the formula will look like

 N*sin(180/N) --> pi

Step-by-step explanation:

6 0
3 years ago
An electrician has 4.1 meters of wire how many strips 7/10 m can he cut . How much wire will he have left
kogti [31]
7/10 m= 0.7 m

4.1÷0.7=5.85 

You would round down 5.85 to just 5, because he cannot cut less than a whole strip.

To find the exact amount of wire used in 5 strips:

5×0.7= 3.5

4.1-3.5= 0.6 m will be leftover.
8 0
2 years ago
If the number of bacteria in a colony doubles every 100 minutes and there is currently a population of 1,500 bacteria, what will
nadya68 [22]
The population will be 6,000
7 0
3 years ago
Differentiating a Logarithmic Function in Exercise, find the derivative of the function. See Examples 1, 2, 3, and 4.
kotykmax [81]

Answer:

f'(x) = -\frac{2x}{1 - x^{2}}

Step-by-step explanation:

The derivative of an addition/subtraction of terms is the addition/subtraction of the derivatives of these terms.

The derivative of a constant is 0.

The derivative of a*x^{n} is a*n*x^{n-1}. The derivative of x^{3} is 3x^{2}, for example.

The derivative of the ln function:

If we have:

y = \ln{g(x)}

The derivative is

y' = g'(x)*\frac{1}{g(x)}

In this problem, we have that:

y = \ln{1 - x^{2}}

So g(x) = 1 - x^{2} and g'(x) = -2x

So the derivative to this function is

f'(x) = -\frac{2x}{1 - x^{2}}

8 0
2 years ago
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