Answer:
Part A: m+1.37=7.9
Part B: 6.53 miles are left to be repaired.
Step-by-step explanation:
Given,
Length of repaired part = 1.37 miles
Total length to be repaired = 7.9 miles
Miles left to be repaired = m
Part A:
Create an equation to show the relationship between the number of miles repaired and the number of miles left to be repaired, m.
Miles left to be repaired + Length of repaired part = Total length to be repaired
m+1.37=7.9
Part B
How many miles are left to be repaired?
Subtracting 1.37 from both sides
6.53 miles are left to be repaired.
Keywords: length, subtraction
Step-by-step explanation:
220 miles in 4 h = 55 mph multiply this by 5280 to get feet per hour then divide this by 60 to get ft/min
According to Greg himself (probably a master at pies) says perfect cherry pies have a ratio of 240 cherries to 3 pies. First, we need to divide 240 cherries by 3 pies to find out how many cherries are in one pie.
240 / 3 = 80
Then multiply by 9 to get your answer.
9 * 80 = 720
Answer:
D
Step-by-step explanation:
So we want to find the equation of the line parallel to y=3x+5 and goes through the point (1,4).
First, since the new line is parallel, its slope must be equivalent. Therefore, the slope of our new line <em>must</em> also be 3.
Now, we can figure out the rest of the equation using the point-slope form:

Substitute 3 for m. Let's let (1,4) be x₁ and y₁. Thus:

Distribute the right:

Add 4 to both sides:

And we're done!
The correct answer is D.
Answer:
0.0668
Step-by-step explanation:
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

Find the probability that the diameter of a selected bearing is greater than 129 millimeters.
This is 1 subtracted by the pvalue of Z when X = 129. So



has a pvalue of 0.9332
1 - 0.9332 = 0.0668
0.0668 = 6.68% probability that the diameter of a selected bearing is greater than 129 millimeters.