We have 55% and 80% antifreeze. We need 90 gallons of 75%.
F - 55% and E - 80%
A) F + E = 90
B) .55 F + .80 E = 67.50 (which is .75 * 90) Multiplying A) by -.55
A) -.55 F -.55 E = -49.50 (which is -.55 * 90) then adding A) & B)
.25 E = 18
E = 72 gallons of 80% and
F = 18 gallons of 55%
********* DOUBLE CHECK ******************
72 * .80 = 57.60 and 18 * .55 = 9.90
57.60 + 9.90 = 67.50 gallons of antifreeze and we have 90 total gallons
(67.50 / 90) * 100 = 75% correct!
Source: 1728.com/mixture.htm
Answer:
option 4
Step-by-step explanation:
using the equation stated above
1st term = -6+(1-1=0)*(6)=-6
4th term= -6+(4-1=3)*6=12
10th term= -6+(10-1=9)*6=48
Answer:
i do not think it is possible to delete a question after you have posted it. if i were you i probably would have just edited it and save myself the emmbarasment
Step-by-step explanation:
Answer:
B
Step-by-step explanation:
10(10m+6)<=12
100m+60<=12 Distributive Property
100m <=12-60
100m <=-48
m <=-48/100
m <=-.48
This says values for m that are less than or equal to -.48
-.48 is between -1 and 0 so the answer is B
Answer: x-1/6
Step-by-step explanation:
